
Area Perimeter Tiling
Authored by Anthony Clark
Mathematics
6th Grade
CCSS covered

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20 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which of the following equations does NOT represent how to find the perimeter, P, of the following shape?
P = LW + LW
P= 2L + W + W
P= 2L + 2W
P= L + L + W + W
Tags
CCSS.4.MD.A.3
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Tyree's dad is tiling the floor in their living room. The living room is 3 yards long and 2 yards wide. The area of each tile is 1 square foot. How many tiles will Tyree's dad need?
6
10
30
54
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Area of rectangle is given by __________
Length + breadth
Length - breadth
Length × breadth
Length / breadth
Tags
CCSS.4.MD.A.3
CCSS.3.MD.C.7B
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Area of a rectangle with length 32 cm and breadth 18 cm is _______.
512 sq. cm
576 sq. cm
544 sq. cm
540 sq. cm
Answer explanation
Option 2 is correct as area of rectangle = Length × breadth = 32 cm × 18 cm = 576 sq. cm
Tags
CCSS.4.MD.A.3
CCSS.3.MD.C.7B
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Area of a rectangular park with length of 65 m and breadth of 42 m is _______.
2665 sq.m
2624 sq.m
2795 sq. cm
2730 sq.m
Answer explanation
Option 4 is correct as area of rectangular park = Length × breadth = 65 m × 42 m = 2730 sq.m
Tags
CCSS.4.MD.A.3
CCSS.3.MD.C.7B
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Area of the given figure is _____.
600 sq. m
330 sq. m
930 sq. m
660 sq.m
Answer explanation
Option 3 is correct as area of figure = area of large rectangle + area of small rectangle = (30 × 20) + (22 × 15) = 600 + 330 = 930 sq. m
Tags
CCSS.3.MD.C.7D
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the cost of tiling a rectangular plot of land 64 m long and 31 m wide at the rate of ₹ 50 per sq m.?
₹ 96000
₹ 99200
₹ 89280
₹ 97650
Answer explanation
Option 2 is correct as area of rectangle = length × breadth = 64 m × 31 m = 1984 sq. m Cost of tiling 1 sq. m = ₹ 50 Cost of titling 1984 sq. m = 1984 × 50 = ₹ 99200
Tags
CCSS.6.G.A.4
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