Holes Vertical Asymptotes and Roots

What are the x-intercept(s) for the function
f(x) = (4x + 12)/(x - 6)

• (-3,0)

• (6,0)

• (0,-2)

• (4,0)

State the vertical asymptote.

• x = -2/5

• x = -5/2

• x = -5

• x = 2

Where is the hole?

• x= 4

• x= -4

• x= 5

• x= -5

The equation of a vertical asymptote is written in the form:

• x=

• y=

• none of the above

Find the vertical asymptote.
g\left(x\right)=\frac{\left(x+3\right)\left(x-2\right)}{\left(x+5\right)\left(2x-1\right)}

• x=-5

• x=1/2

• x=-1/2

• x=-3

• x=2

The holes of a rational function occur when :

• my pencil pokes a hole in the paper I'm working on

• there is something left in the denominator

• the value of f(0)

• a factor in the denominator cancels with a factor in the numerator

• 2

• -2

• -6

• 6

Identify the x-value of the hole(s).

• x=0

• x=-3

• x=6

• x=-7

• x=3

Find the vertical asymptote.
f\left(x\right)=\frac{x^2-2x-8}{3x-2}

• y=2/3

• x=3/2

• x= 2/3

• x=1/3

What are the coordinates of the hole, if one exists.

• (-1, -2)

• (-1, ½)

• (-1, -½)

• there isn't one