Geometry Proofs Vocabulary

Geometry Proofs Vocabulary

10th Grade

10 Qs

quiz-placeholder

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Geometry Proofs Vocabulary

Geometry Proofs Vocabulary

Assessment

Quiz

Mathematics

10th Grade

Hard

CCSS
7.G.B.5, 4.G.A.1, 8.G.A.5

+3

Standards-aligned

Created by

Anthony Clark

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

When trying to prove two angles are supplementary, what must you show in your proof?

that the angles are equal

that the angles add up to 180 degrees

that the angles are a linear pair

that the angles are right angles

Tags

CCSS.7.G.B.5

2.

MULTIPLE CHOICE QUESTION

1 min • 5 pts

m<AMX + m<XMB = m<AMB

Segment addition postulate

Angle addition postulate

Definition of supplementary angles

Definition of angle bisector

Tags

CCSS.8.G.A.5

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What should you conclude by definition of perpendicular?

<ORP is a right angle

QR + RP = QP

<ORQ and <ORP are complementary

Tags

CCSS.4.G.A.1

CCSS.HSG.CO.A.1

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Given: <1 and <3 are vertical angles. What should you conclude by the vertical angles theorem?

<1 and <2 are a linear pair

<1 and <3 are right angles

<2 and <4 are vertical angles

Tags

CCSS.7.G.B.5

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Given: <1 and <2 are a linear pair. Conclusion: m<1 + m<2 = 180. What is the reason that allows you to draw that conclusion?

Angle addition postulate

Definition of straight angle

Linear Pair Postulate

Definition of supplementary

Tags

CCSS.7.G.B.5

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Given: AB is the segment bisector of PQ. What conclusion can you draw?

PF = QF

F is the midpoint of PQ

m<PFA = m<QFA

<PFQ is a straight angle

Tags

CCSS.HSG.CO.C.10

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Which of the following CAN you conclude from the diagram?

lines l and m are perpendicular

<a and <b are adjacent

<a and <b are complementary

m<a = m<b

Tags

CCSS.4.G.A.1

CCSS.HSG.CO.A.1

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