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Triangle Proofs Practice

Authored by Anthony Clark

Mathematics

10th Grade

CCSS covered

Triangle Proofs Practice
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20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What is the "reason" for step 5 of the proof?

Angle Bisector Theorem

Reflexive property

CPCTC Theorem

Proof

Tags

CCSS.HSG.SRT.B.5

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Fill in the Reason.

Opposite sides of a parallelogram are congruent.

definition of parallelogram

Prove

CPCTC

Tags

CCSS.HSG.CO.C.11

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What is the reason?

Definition of Complementary

Definition of 180 

Definition of supplementary

Angle Addition

Tags

CCSS.7.G.B.5

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Name the property of equality or congruence that justifies going from the first statement to the second statement.

Reflexive Property of Congruence

Symmetric Property of Congruence

Distributive Property

Transitive Property of Congruence

Tags

CCSS.HSG.SRT.B.5

5.

DRAG AND DROP QUESTION

1 min • 1 pt

Media Image

Statements Reasons

∠1 ≅ ∠2

JG bisects EH at F

EF ≅ FH

∠3 ≅ ∠4

△EFJ ≅ △HFG

∠EJF ≅ ∠HGF

EJ ≅ GH

JF ≅ FG

Definition of bisect

Definition of midpoint

Tags

CCSS.HSG.SRT.B.5

6.

DRAG AND DROP QUESTION

1 min • 1 pt

Media Image

Statements Reasons

∠DBM ≅ ∠FCM

∠BDM ≅ ∠CFM

M is the midpoint of DF

DM ≅ MF

△BDM ≅ △CFM

∠BMD ≅ ∠CMF

BM ≅ CM

BD ≅ CF

Definition of midpoint

Definition of bisect

Tags

CCSS.HSG.SRT.B.5

7.

DRAG AND DROP QUESTION

1 min • 1 pt

Media Image

Statements Reasons

1. ∠A ≅ ∠C 1. ​ (a)  

2. BD bisects ∠ABC 2. ​ (b)  

3. ∠DBA ≅ ∠DBC 3. ​ (c)  

4. BD ≅ BD 4. ​ (d)  

5. △ABD ≅ △CBD 5. ​ (e)  

Given

Definition of bisect

Reflexive

AAS

Definition of midpoint

SSS

SAS

ASA

Vertical Angles Theorem

Linear Pairs Theorem

Tags

CCSS.HSG.SRT.B.5

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