Factoring Polynomial and Zero

Complete the factoring:

x² - 12x + 32 is factored into (x-8)(___)

• x - 4

• x + 4

• x² + 8

• 8 - x

Factor Completely:

18x² - 78x - 60

• 6(3x - 2)(x + 5)

• (18x +12)(x - 5)

• Prime

• 6(3x + 2)(x - 5)

Factor Completely:

2r² -17rt + 8t²

• Prime

• (2r + t)( r - 8t)

• (2r + t)(r + 8t)

• (2r - t)(r - 8t)

Factor Completely:

x² + 3x - 28

• (x - 7)(x - 4)

• (x - 7)(x + 4)

• (x + 7)(x - 4)

• ( x + 7)(x + 4)

The polynomial 10x³+35x² - 4x -14 is partially factored by grouping.

5x² (_____) - 2(_____)

What is the common factor that is missing from both sets of parenthesis?

• -2x - 7

• 2x + 7

• -2x² +7

• 2x² + 7

Factor completely:

Tags

CCSS.HSA.APR.C.4

if the product of two factors is 0, then at least one of the factors must be 0

• Zero Product Property

• factoing

• binomial

• prime polynomial

Tags

CCSS.HSA-REI.B.4B

a polynomial that cannot be written as a product of two polynomials with integral coefficients

• prime polynomial

• monomial

• perfect square trinomial

• degree of a polynomial

Solve by Factoring:  4x² + 11x - 3 = 0

• x = -3/4 and x = -1

• x = 4 and x = 3

• x = 1/4 and x = -3

• x = -1/4 and x = 3

Tags

CCSS.HSA-REI.B.4B

Factor:
 f(x) = x³-12x²+47x-60=0 when 5 is a zero. (so f(5) = 0)

• (x-3)(x-4)(x-5)=0

• (x+1)(x-4)(x-5)=0

• (x-3)(x-4)(2x-5)=0

• (x-5)(x-4)(x-5)=0

Tags

CCSS.HSA.APR.B.2