Ordered Pair Rules Transformations

If a is greater than 1, the image is congruent to the pre-image.

If a is between 1 and 1, the image is congruent to the pre-image.

If a is greater than 1, the image is smaller that the pre-image.

If a is between 0 and 1, the image is smaller than the pre-image.

$$\left(-\frac{3}{n},\ -\frac{5}{n}\right)$$

$$\left(-3n,\ -5n\right)$$

$$\left(-3+n,\ -5+n\right)$$

$$\left(-3-n,\ -5-n\right)$$

$$\left(x,\ y\right)\rightarrow\ \left(\frac{2}{7}x,\ \frac{2}{7}y\right)$$

$$\left(x,\ y\right)\rightarrow\ \left(x+15,\ y+5\right)$$

$$\left(x,\ y\right)\rightarrow\ \left(x-15,\ y-5\right)$$

$$\left(x,\ y\right)\rightarrow\ \left(\frac{7}{2}x,\ \frac{7}{2}y\right)$$

$$\left(\frac{3}{7}x,\ \frac{3}{7}y\right)$$

$$\left(x+\frac{7}{3},\ y+\frac{7}{3}\right)$$

$$\left(x+\frac{3}{7},\ y+\frac{3}{7}\right)$$

$$\left(\frac{7}{3}x,\ \frac{7}{3}y\right)$$

$$\left(\frac{3}{2}x,\ \frac{3}{2}y\right)$$

$$\left(x+\frac{3}{2},\ y+\frac{3}{2}\right)$$

$$\left(\frac{2}{3}x,\ \frac{2}{3}y\right)$$

$$\left(x+\frac{2}{3},\ y+\frac{2}{3}\right)$$

$$\left(x,\, y\right)\rightarrow\ \left(-x,\, -y\right)$$

$$\left(x,\, y\right)\rightarrow\ \left(x,\, -y\right)$$

$$\left(x,\, y\right)\rightarrow\ \left(-y,\, -x\right)$$

$$\left(x,\, y\right)\rightarrow\ \left(-x,\, y\right)$$

$$\left(x,\ y\right)\rightarrow\ \left(x,\ -y\right)$$

$$\left(x,\ y\right)\rightarrow\ \left(-x,\ y\right)$$

$$\left(x,\ y\right)\rightarrow\ \left(y,\ x\right)$$

$$\left(x,\ y\right)\rightarrow\ \left(y,\ -x\right)$$

$$\left(x,\, y\right)\rightarrow\ \left(x,\, -y\right)$$

$$\left(x,\, y\right)\rightarrow\ \left(x,\, y+8\right)$$

$$\left(x,\, y\right)\rightarrow\ \left(-y,\, x\right)$$

$$\left(x,\, y\right)\rightarrow\ \left(-x,\, y\right)$$

$$\left(x,\ y\right)\rightarrow\ \left(6x,\ -4y\right)$$

$$\left(x,\ y\right)\rightarrow\ \left(-6x,\ 4y\right)$$

$$\left(x,\ y\right)\rightarrow\ \left(x+6,\ y-4\right)$$

$$\left(x,\ y\right)\rightarrow\ \left(x-6,\ y+4\right)$$

$$\left(x,\ y\right)\rightarrow\ \left(x,\ y-7\right)$$

$$\left(x,\ y\right)\rightarrow\ \left(x,\ -y\right)$$

$$\left(x,\ y\right)\rightarrow\ \left(x-7,\ y\right)$$

$$\left(x,\ y\right)\rightarrow\ \left(-x,\ y\right)$$