Soh Cah Toa Angle Measure

Find sinC

• 21/35

• 28/21

• 35/28

• 28/35

Tags

CCSS.HSG.SRT.C.6

Find the measure of the indicated angle.

• 9.39

• 55.2

• 20.2

• 19.4

Tags

CCSS.HSG.SRT.C.8

What is the correct ratio to solve for w?

• sin 40 = w/28

• cos 40 = w/28

• tan 40 = w/28

• sin 40 = 28/w

Tags

CCSS.HSG.SRT.C.6

Find cosA

• 30/16

• 30/34

• 30/15

• 16/34

Tags

CCSS.HSG.SRT.C.6

• 38.66
• 36.87
• 53.13
• 45.71

Tags

CCSS.HSG.SRT.C.8

Consider SOH - CAH - TOA, what does CAH stand for?

• sin⁡θ=oppositehypotenuse\sin\theta=\frac{opposite}{hypotenuse}

  sinθ=hypotenuse

  
  

  opposite

  ​

• cos⁡θ=adjacenthypotenuse\cos\theta=\frac{adjacent}{hypotenuse}

  cosθ=hypotenuse

  
  

  adjacent

  ​

• tan⁡θ=oppositeadjacent\tan\theta=\frac{opposite}{adjacent}

  tanθ=adjacent

  
  

  opposite

  ​

• tan⁡θ=sin⁡θcos⁡θ\tan\theta=\frac{\sin\theta}{\cos\theta}

  tanθ=cosθ

  
  

  sinθ

  ​

Tags

CCSS.HSG.SRT.C.6

Consider SOH - CAH - TOA, what does SOH stand for?

• sin⁡θ=oppositehypotenuse\sin\theta=\frac{opposite}{hypotenuse}

  sinθ=hypotenuse

  
  

  opposite

  ​

• cos⁡θ=adjacenthypotenuse\cos\theta=\frac{adjacent}{hypotenuse}

  cosθ=hypotenuse

  
  

  adjacent

  ​

• tan⁡θ=oppositeadjacent\tan\theta=\frac{opposite}{adjacent}

  tanθ=adjacent

  
  

  opposite

  ​

• tan⁡θ=sin⁡θcos⁡θ\tan\theta=\frac{\sin\theta}{\cos\theta}

  tanθ=cosθ

  
  

  sinθ

  ​

Tags

CCSS.HSG.SRT.C.6

• 32.58
• 57.42
• 31.44
• 59.02

Tags

CCSS.HSG.SRT.C.8

What does SOH stand for

• hypotenuse over opposite

• adjacent over opposite
  opposite over adjacent

• opposite over hypotenuse

• adjacent over adjacent

Tags

CCSS.HSG.SRT.C.8

 FInd tanX

• 32/40

• 40/24

• 32/24

• 24/32

Tags

CCSS.HSG.SRT.C.6