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Six Trigonometric Values in a Unit Circle

Authored by Anthony Clark

Mathematics

11th Grade

CCSS covered

Six Trigonometric Values in a Unit Circle
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20 questions

Show all answers

1.

OPEN ENDED QUESTION

1 min • 1 pt

Find the exact values of the six trigonometric functions of the given angle. Do not use a calculator.

390°

Evaluate responses using AI:

OFF

Tags

CCSS.HSF.TF.C.8

2.

OPEN ENDED QUESTION

1 min • 1 pt

The point given below is on the terminal side of an angle θ in standard position. Find the exact value of each of the six trigonometric functions of θ.

(10,−24)

Evaluate responses using AI:

OFF

Tags

CCSS.HSF.TF.A.2

3.

OPEN ENDED QUESTION

1 min • 1 pt

Use reference angles to find the exact value of the following expression.

cos(300°)

Evaluate responses using AI:

OFF

Tags

CCSS.HSF.TF.A.2

4.

OPEN ENDED QUESTION

1 min • 1 pt

Find the exact value of sin α​, given that cos α= 8/11 and α is in quadrant I.

Evaluate responses using AI:

OFF

Tags

CCSS.HSF.TF.C.8

5.

FILL IN THE BLANKS QUESTION

1 min • 1 pt

Media Image

What is the length of the hypotenuse of the triangle? (Think about it as a radius)

OP= (a)  

Label OP on your paper.

Tags

CCSS.HSF.TF.A.2

6.

DRAG AND DROP QUESTION

1 min • 1 pt

Let θ represent an angle on the unit circle, with 0≤θ≤π20\le\theta\le\frac{\pi}{2} , such that tan⁡θ=33\tan\theta=\frac{\sqrt[]{3}}{3} .

Drag and drop the correct answer into each blank.

sin⁡(3θ)=\sin\left(3\theta\right)= ​ (a)  

cos⁡(−4θ)=\cos\left(-4\theta\right)= ​ (b)  

11  

−12-\frac{1}{2}  

undefined

−1-1

12\frac{1}{2}

32\frac{\sqrt[]{3}}{2}

−32-\frac{\sqrt[]{3}}{2}

00

22\frac{\sqrt[]{2}}{2}

−22-\frac{\sqrt[]{2}}{2}

Answer explanation

Media Image

Tags

CCSS.HSF.TF.C.9

7.

DRAG AND DROP QUESTION

1 min • 1 pt

Let θ represent an angle on the unit circle, with 0≤θ≤π20\le\theta\le\frac{\pi}{2} , such that tan⁡θ=33\tan\theta=\frac{\sqrt[]{3}}{3} . Drag and drop the correct answer into each blank. sin⁡(3θ)=\sin\left(3\theta\right)= ​ (a)   cos⁡(−4θ)=\cos\left(-4\theta\right)= ​ (b)  

11  

−12-\frac{1}{2}  

undefined

−1-1

12\frac{1}{2}

32\frac{\sqrt[]{3}}{2}

−32-\frac{\sqrt[]{3}}{2}

00

22\frac{\sqrt[]{2}}{2}

−22-\frac{\sqrt[]{2}}{2}

Answer explanation

Media Image

Tags

CCSS.HSF.TF.C.9

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