Quadratic Functions Written as the Product of Two Binomials

The product of the square of a binomial, consists of how many terms?

• 6 terms

• 3 terms

• 9 terms

• 4 terms

to multiply two binomials, find the sum of the products of the 1st terms, the Outside terms, the Inside terms, and the Last terms

• FOIL method

• factoring by grouping

• difference of two squares

• quadratic equation

• quadratic equation

• prime polynomial

• trinomial

• Zero Product Property

Write the equation of the quadratic function that has a x-intercepts at (2, 0) and (4, 0) and passes through the point (3, 4) in factored form. Do not use spaces! y=

Answer explanation

Use the x-intercepts to write the two factors, remember you have to use the OPPOSITE sign!

Then substitute in the other point for x and y, then go forward in solving for a. Remember, the side with the factors is all multiplication! You are only adding/subtracting inside the parentheses, then multiplying those together, and those times a. That means your last step is division.

Write a quadratic function with roots of -7 and -3.

• y = (x+7)(x+3)

• y = (x-7)(x+3)

• y = (x+7)(x-3)

• y = (x-7)(x-3)

Write a quadratic function with roots of 11 and 29.

• y = (x+11)(x+29)

• y = (x+11)(x-29)

• y = (x-11)(x+29)

• y = (x-11)(x-29)

Write the equation of the quadratic if it goes through (-1, 2) and has the given intercepts.

• y=5/2 (x-0)(x-4)

• y = 2/5 (x-0)(x-4)

• y= 2/3 (x-0)(x-4)

• y= 3/2 (x-0)(x-4)

Find the product:
(3x + 2)(2x + 4)

• 6x² + 16x + 8

• 5x² +11x + 6

• 5x² + 16x + 6

• 6x² + 11x + 8

Write a quadratic function with roots of -2 and 1.

• y = (x+2)(x+1)

• y = (x+2)(x-1)

• y = (x-2)(x+1)

• y = (x-2)(x-1)