Find the Point of a Circle Using the Equation

What is the center and radius given the equation, x² + y² + 8x - 2y - 64 = 0?

• Center: (-4, 1), Radius: 9

• Center: (4,1), Radius: 8

• Center: (1,-4), Radius: 64

• Center: (-4, 1), Radius: 81

Tags

CCSS.HSG.GPE.A.1

What is the center of the circle with equation x² + y² = 1?

• (1, 1)

• (0, 0)

• (0,1)

• not enough information

Tags

CCSS.HSG.GPE.A.1

What are the coordinates of the center and the radius of the circle with equation:
(x - 4)² + (y - 3)² = 25 ?

• Center (4,3)
  Radius = 5 units

• Center (4,3)
  Radius = 25 units

• Center (-4,-3)
  Radius = 25 units

• Center (-4,-3)
  Radius = 5 units

Tags

CCSS.HSG.GPE.A.1

In the equation (x-3)²+(y-2)²=16, the center of the circle is...

• (3,2)

• (-3, -2)

• (-2, -3)

• (2, 3)

Tags

CCSS.HSG.GPE.A.1

Tags

CCSS.HSG.GPE.A.1

Tags

CCSS.HSG.GPE.A.1

What is the center for the circle with this equation x²+y²+4x+6y-36=0?

• (4,6))

• (2,3)

• (-2,-3)

• (-4, -6)

Tags

CCSS.HSG.GPE.A.1

• (x + 3)² + (y - 1)² = 9
• (x - 3)² + (y + 1)² = 9
• (x - 3)² + (y + 1)² = 3
• (x + 3)² + (y - 1)² = 3

Tags

CCSS.HSG.GPE.A.1

• (x - 1)² + (y + 2)² = 2

• (x + 2)² + y² = 4

• x² + (y + 2)² = 4

• x² + (y + 2)² = 2

Tags

CCSS.HSG.GPE.A.1

What does (h,k) stand for in the standard circle equation?

• (h,k) is the center of the circle

• (h,k) is a point on the circle.

• (h,k) is a point that we guess and find

• (h,k) is the distance of the circle

Tags

CCSS.HSG.GPE.A.1