Equation of a Circle Geometry

Determine the equation of the circle in standard form: x² + y² + 6x - 12y + 20 = 0

• (x-3)² + (y+6)² = 25

  
  

• (x+3)² + (y-6)² = 25

  
  

• (x-3)² + (y+6)² = 45

  
  

• (x+3)² + (y-6)² = 5

  
  

Determine the center and radius:

x² + y² - 10x + 8y -8 = 0

• C = (5,-4) r = 7

• C = (-5,4) r = 7

• C = (-4,5) r = 49

• C = (5,-4) r = 7

What is the radius of the equation of circle: x²+y²-12x-12y-28=0

• 28

• 36

• 100

• 10

What is the radius of the equation of circle: x²+y²-10x-14y+38=0

• 6

• 49

• -38

• 36

Write the standard equation for the following image

• (x-2)²+(y+1)²=9

• (x+2)²+(y-1)²=9

• x²+y²+4x-2y-4=0

• (x+2)²+(y-1)²=3

Find the center and radius of the circle given by the equation: x² + y² - 6x + 4y + 9 = 0

• Center = (3, -2), Radius = 2

• Center = (-3, 2), Radius = 4

• Center = (3, -2), Radius = 4

• Center = (-3, 2), Radius = 2

What is the radius of the following equation (x+7)²+(y-9)²=25

• 25

• 5

• 7

• 9

Write the equation in standard form for the circle 0=-x²-y²-14y+14

• x²+y²+14y=63

• x²+(y+7)²=49

• x²+(y+7)²=63

• -x²+(y-7)²=35

Determine the center and radius: x² + y² + 14x - 2y = -1

• center= (-7,2) radius= 3

• center= (-7,1) radius= 7

• center= (-4,1) radius= 5

  
  

Identify the center of the circle in general form.

x²+y²-20x+14y+129=0

• (-10,-7)

• (10,-7)

• (20,14)

• (-20,14)