Mean Median Standard Deviation

Quiz
•
Mathematics
•
9th Grade
•
Hard
Anthony Clark
FREE Resource
20 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
To find the _________ you add up all the numbers and then divide by how many numbers you have.
Mean
Median
Mode
Range
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The term "snowstorms of note" applies to all snowfalls over 6 inches. The snowfall amounts for snowstorms of note in Utica, New York, over a four-year period are as follows: 7.1, 9.2, 8.0, 6.1, 14.4, 8.5, 6.1, 6.8, 7.7, 21.5, 6.7, 9.0, 8.4, 7.0, 11.5, 14.1, 9.5, 8.6 What are the mean and SAMPLE standard deviation for these data, to the nearest hundredth?
mean = 9.46; standard deviation = 3.74
mean = 9.46; standard deviation = 3.85
mean = 9.45; standard deviation = 3.74
mean = 9.45; standard deviation = 3.85
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
If test scores for a class are: 100, 100, 90, 90, 80, 80, 70, 70, 60, and 60, what are the mean and sample standard deviation?
mean = 80, stdev = 14.9
mean = 70, stdev = 14.9
mean = 80, stdev = 13.9
mean = 80, stdev = 12.9
mean = 85, stdev = 14.9
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the sample standard deviation for the data given:
5, 10, 7, 12, 0, 20, 15, 22, 8, 2
6.89
10.1
7.26
9
5.
MULTIPLE CHOICE QUESTION
1 min • 5 pts
Michael has taken 12 tests in his math class. His lowest test score was 78. His highest test score was 98. On the 13th test, he earned a 64. Which of the following effects are certain to occur to the standard deviation, mean, and median of Michael's test scores when the last score is added?
The standard deviation, median, and mean all decrease.
The standard deviation increases, mean decreases, and median cannot be determined.
The standard deviation increases, and mean and median decrease.
The standard deviation cannot be determined, and mean and median decrease.
6.
MULTIPLE CHOICE QUESTION
1 min • 5 pts
Which is true?
Mean < Median
Mean = Median
Mean > Median
7.
MULTIPLE CHOICE QUESTION
1 min • 5 pts
Which is true?
Mean < Median
Mean = Median
Mean > Median
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