Graphing and Solving Equation Review
Authored by Anthony Clark
Mathematics
9th Grade
CCSS covered
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15 questions
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1.
DRAG AND DROP QUESTION
1 min • 5 pts
In this system
x+3y=9
4x-2y=-6
it'll be easiest to start by solving the first equation for x.
The result of doing so is x=9-3y.
Fill in the blanks to plug that expression in and solve for y:
4( (a) )-2 (b) =-6
36- (c) y-2y= (d)
36- (e) =-6
9-3y
y
12
-6
14y
x
10y
x+3y
24y
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
2.
DRAG AND DROP QUESTION
1 min • 2 pts
In this system
x+3y=9
4x-2y=-6
it'll be easiest to start by solving the first equation for x.
The result of doing so is x=9-3y.
Fill in the blanks to plug that expression in and solve for y:
4(9-3y)-2y =-6
36-12y-2y=-6
36-14y =-6
-14y= (a)
y= (b)
-42
3
30
-3
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
3.
DRAG AND DROP QUESTION
1 min • 5 pts
In this system
x+3y=9
4x-2y=-6
we have figured out that x=9-3y, and y=3.
Complete the steps to solve for x:
x=9-3( (a) )
x=9- (b)
x= (c)
The solution to the system is ( (d) , (e) ).
3
9
0
y
x
y=3
3y
-9
18
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
4.
DRAG AND DROP QUESTION
1 min • 3 pts
Consider the system
4x+3y=-1
5x+4y=1
Let's say I want to eliminate the y's. What is the least common multiple of 3 and 4?
LCM = (a)
Multiply each equation by a number so that the coefficient of y will be 12, with one positive and one negative.
(b) (4x+3y=-1)
(c) (5x+4y=1)
12
4
-3
3
5
1
-1
-12
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
5.
DRAG AND DROP QUESTION
1 min • 5 pts
Consider the system
4x+3y=-1
5x+4y=1
After we do this multiplication, what will the new equations be?
4(4x+3y=-1) ---> (a) x + (b) y= (c)
-3(5x+4y=1) ---> (d) x - (e) y= -3
16
12
-4
-15
3
5
1
-1
-12
-3
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
6.
DRAG AND DROP QUESTION
1 min • 4 pts
Consider the system:
4x+3y=-1
5x+4y=1
Which we converted to:
16 x + 12y=-4
-15x - 12y= -3
Combining the equations straight down gives us:
(a) x+ (b) y= (c)
Solving for x, we get x= (d)
1
0
-7
3
5
-1
-12
-3
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
7.
DRAG AND DROP QUESTION
1 min • 5 pts
Consider the system:
4x+3y=-1
5x+4y=1
Since we now know that x=-7, solve for y:
4( (a) )+3y=-1
(b) +3y=-1
(c) = (d)
y= (e)
-7
-28
3y
27
9
5
7
-12
3
y
Tags
CCSS.HSA.REI.C.9
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