Substituting Systems of Equation Solutions

The first step in solving a system of equations using the SUBSTITUTION METHOD is __________.

(Read all the answers before choosing one.)

• get x by itself

• get y by itself

• get EITHER x or y by itself

• add the equations together

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Which answer has a correct next step for this system? (Read all three answers carefully before selecting one!)

• The variable is already isolated, so we've already solved the system.

• The variable is already isolated for y, so we substitute it in the second equation like this:

  2(6x) + 5y = 32

• The variable is already isolated for y, so we substitute it in the second equation like this:

  2x + 5(6x) = 32

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Use the system of equations below to answer the question. After substituting the first equation into the second one and working it out, I got x = 1. What should I do next?

• Fill in 1 for x in y = 6x

• Fill in 1 for y in y = 6x

• Fill in 1 for y in 2x + 5y = 32

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Which answer has a correct next step for this system? (Read all three answers carefully before selecting one!)

• The variable is already isolated, so we've already solved the system.

• The variable is already isolated for y, so we substitute 3x + 5 in the first equation like this:

  3x + 4(3x + 5) = 3

• The variable is already isolated for y, so we substitute 3x + 5 in the second equation like this:

  3(3x + 5) + 4y = 3

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

7. Solve the system of linear equations: 2x + 5y = 13 and 3x - 2y = 4

• x = 4, y = 4

• x = 3, y = 1

• x = 2, y = 3

• x = 5, y = 2

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the solution to this system? Solve by substitution.
y= 4x + 3
2x - 3y = 21

• (3,-9)

• (-3,-9)

• (-3,9)

• (0,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following system of equations: 5x - 4y = 3 and 2x + 3y = 8

• x = 4, y = 3

• x = 2, y = 1

• x = 3, y = 2

• x = 1, y = 5

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

10. Solve the following system of equations: 5x - 4y = 3 and 2x + 3y = 8

• x = 4, y = 3

• x = 2, y = 1

• x = 3, y = 2

• x = 1, y = 5

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

solve by substitution: y=3x+14
y=-4x

• y=3

• y=1

• y= - 2

• y=4

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• No Solution

• (2, 2)

• (-1, 2)

• (-1, -2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6