Conditional Probability Tree Diagrams

If there are 3 red sections, 4 blue sections, and 1 green section on a spinner, then...

P(Green ∩ Blue) =

Round your answer to 3 decimal spaces as necessary.

(a)  

If there are 3 red sections, 4 blue sections, and 1 green section on a spinner, then... Are the event green and blue independent? Select an answer and a justification.

• Yes

• No

• because P(A) = P(A|B)

• because P(A) ≠ P(A|B)

If there are 3 red sections, 4 blue sections, and 1 green section on a spinner, then...

P(Red) =

Round your answer to 3 decimal spaces as necessary.

(a)  

What is the probability of randomly choosing a breakfast with a bagel and coffee?

• 1/8 because there is only 1 outcome out of the 8 possible choices that include both a bagel and coffee.

• 1/2 because there is only cereal and a bagel to choose from

• 1/4 because there is only one out of the four choices that include coffee

• 3 because the words "coffee" and "bagel" are on the diagram a total of 3 times.

For breakfast, you can choose to eat cereal or a bagel and to drink coffee, OJ, tea, or water. What is the sample space of this situation?

• 2, because there are 2 things to choose from to eat.

• 4, because there are 4 things to choose from to drink

• 10, because I see 10 different words on the tree diagram

• 8, because there are 8 different outcomes (cereal, coffee) (cereal, OJ) (cereal, tea) (cereal, water) (bagel, coffee) (bagel, OJ) (bagel, tea) (bagel, water)

What is the probability of randomly picking a lunch with pizza, soda, and ice cream?

• 1/18

• 3/18 or 1/6

• 13/18

• 1/3

Q1. How many legs does a spider have?

• A) 6

• B) 12

• C) 2

• D) 10

The tree diagram shows the outcomes of rolling a die and flipping a coin.  
How many total outcomes are there?  

• 6

• 12

• 24

• 36

There are 10 counters in a bag, 3 red and 7 blue.

I take one counter, then another without replacement.

Find the probability of the value marked w

• ⁷/₁₀

• ³/₁₀

• ⁶/₉

• ²/₉

There are 10 counters in a bag, 3 red and 7 blue.

I take one counter, then another without replacement.

Find the probability of picking two red counters.

• ⁶/₉₀

• ⁵/₁₉

• ⁴⁷/₉₀

• ²/₉