Rewriting Standard Form to Vertex

Determine the vertex of the parabola y=5(x-2)²–7

• (5, -7)

• (-2, -7)

• (2, -7)

• (-7, -2)

• A
• B
• C
• D

Convert f(x) = 3x²+ 6x - 5 to vertex form.

• f(x) = 3(x + 1)² - 8

• f(x) = 3(x - 1) ² - 8

• f(x) = 3(x + 2)² - 8

• f(x) = 3(x - 2)² - 8

Convert f(x) = 4x² - 32x + 2 to vertex form.

• f(x) = 4(x + 4)² - 62

• f(x) = 4(x - 4)² - 62

• f(x) = 4(x - 8)² - 62

• f(x) = 4(x + 8)² - 62

Convert to vertex form.

• y=2(x+3)² - 9

• y=2(x-3)² - 9

• y=2(x+6)² - 9

• y=2(x-6)² - 9

Convert to vertex form.

• y=1/3(x+3)² - 29

• y=1/3(x-3)² - 29

• y=1/3(x-9)² - 29

• y=1/3(x+9)² - 29

Convert the equation f(x) = x² - 12x + 40 into vertex form

• f(x) = (x + 6)² - 4

• f(x) = (x + 6)² + 4

• f(x) = (x - 6)² - 4

• f(x) = (x - 6)² + 4

If given the equation
y = 3(x + 5)² - 4,
what is the vertex of the parabola?

• (5, -4)

• (-5, -4)

• (-15, -4)

• (15, -4)

Convert to vertex form.

• y=-2(x+12)² + 77

• y=-2(x-12)² + 77

• y=-2(x-6)² + 77

• y=-2(x+6)² + 77

Write a quadratic equation that opens up, has a vertex of (1, -3)and passes through (-4, 6)

• y = 2(x - 1)² - 3

• y=3(x+1)² + 3

• y = 9/25(x - 1)² - 3

• x = 9/25(y + 3)² - 1