Systems of Equations Adding

Systems of Equations Adding

9th Grade

20 Qs

quiz-placeholder

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Systems of Equations Adding

Systems of Equations Adding

Assessment

Quiz

Mathematics

9th Grade

Hard

Created by

Anthony Clark

FREE Resource

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Solve this system of equations, step by step.
-2x - 8y = 10
2x - 6y = 18
What is the result if you add these equations together?

4x - 14y = 28

14y = 28

2y = 8

-14y = 28

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

When you added the system, the result was 
      -14y = 28
Now, solve for y.
   

y = -2

y = 2

y = -7

y = 7

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Write the solution for the system of equations
-5x - 4y = -15
 -x + 4y = -3

(-3. 0)

(0, -3)

(3, 0)

(-3, 0)

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Write the solution for the system of equations
3x + 2y = -12
4x - 2y = -2

(-2, -3)

(-2, 3)

(2, -3)

(2, 3)

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A customer at a store paid $64 for 3 large candles and 4 small candles. At the same store, a second customer paid $4 more than the first customer for 1 large candle and 8 small candles. The price of each large candle is the same, and the price of each small candle is the same. Which system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y?

4y = 3x + 64

8y = x + 68

4y = 3x + 64

8y = x + 60

3x + 4y = 64

x + 8y = 68

3x + 4y = 64

x + 8y = 60

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Solve the system. 

(5, -6, 3)

(2, 3, -1)

(-4, 2, 5)

No Solution

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A customer at a store paid $64 for 3 large candles and 4 small candles. At the same store, a second customer paid $68 for 1 large candle and 8 small candles. The price of each large candle is the same, and the price of each small candle is the same. Which system of equations can be used to find the price in dollars of each large candle, x, and each small candle, y?

4y = 3x + 64

8y = x + 68

4y = 3x + 64

8y = x + 60

3x + 4y = 64

x + 8y = 68

3x + 4y = 64

x + 8y = 60

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