Solving Linear Equation With One Variable On One Side

Solve the equation: 3(x + 2) = 15

• x = 5

• x = 3

• x = 6

• x = 7

Tags

CCSS.7.EE.B.4A

Solve the equation: 2(4x - 3) = 10

• 2

• 5

• 4

• 3

Tags

CCSS.7.EE.B.4A

Solve the equation: 5(2x + 1) - 3 = 22

• 3

• 4

• 2

• 5

Tags

CCSS.7.EE.B.4A

Solve the equation: 4(3x - 2) + 5 = 23

• 7/4

• 5/2

• 2/3

• 13/6

Tags

CCSS.7.EE.B.4A

Solve the equation: 6(3x - 2) - 4 = 26

• 10/3

• 5/3

• 8/3

• 7/3

Tags

CCSS.7.EE.B.4A

Solve the equation: 2(4x + 3) + 5 = 23

• 2.5

• 3

• 1.5

• 4

Tags

CCSS.7.EE.B.4A

Solve the equation: 3(2x - 1) - 4 = 11

• 4

• 5

• 6

• 3

Tags

CCSS.7.EE.B.4A

Solve the equation: 5(3x + 2) + 1 = 36

• 7

• 5/3

• 10

• 12

Tags

CCSS.7.EE.B.4A

Explain the concept of 'solving for a variable' in the context of literal equations.

• Multiplying the variable by a constant

• Dividing the variable by a constant

• Adding the variable to both sides of the equation

• Isolating the variable on one side of the equation

Tags

CCSS.HSA.CED.A.4

What is the purpose of 'isolating a variable' in a literal equation?

• To solve for the variable and find its value

• To hide the value of the variable

• To make the equation more complicated

• To make the variable more confusing

Tags

CCSS.HSA.CED.A.4