Solving Two-Step Equation Find the Error

2x - 3 + 4x = 27

• 12

• 4

• 5

• 15

Tags

CCSS.8.EE.C.7B

Find the error in the problem below
19 - 2k = 3k - 1
     +3k   +3k
19 + 1k = -1
-19           -19
k = -20

• They should have divided by 1 for the last step

• They should add 19 instead of subtracting 19

• I can not find an error

• Instead of adding 3k they should subtract 3k

Tags

CCSS.HSA.REI.A.1

Which is the correct first step in solving the equation shown?

• Subtract 33 from both sides

• Add 33 from both sides

• Add 3.5 from both sides

• Multiply both sides by -3.5

Tags

CCSS.7.EE.B.4A

Austin solved the equation as shown below. Which correctly describes the error that Austin made in his work?

• Austin did not combine 7x and 8x correctly.

• Austin did not combine -3 and -9 correctly.

• Austin did not divide correctly.

• Austin did not make an error in his work.

Tags

CCSS.HSA.REI.A.1

How many solutions does the following equation have:

2(9x – 6) = 6(3x – 2) + 2

• One solution

• Two solutions

• No solution

• Infinitely many: all real numbers

Tags

CCSS.8.EE.C.7A

Solve the equation below.

• 18.8

• -14.8

• 24

• -24

Tags

CCSS.7.EE.B.4A

Did Sarah make an error? If so, which is the best description of her error?

• She didn't distribute correctly. The second step should read 3x - 12 = 24

• She didn't distribute correctly. The second step should read -3x - 12 = 24

• She didn't distribute correctly. The second step should read -3x + 12 = 24

• She didn't make an error.

Tags

CCSS.HSA.REI.A.1

The steps in solving 5b - 6 = 24 are: 

• Add 6 to both sides and divide both sides by 5

• Add 6 to both sides and multiply both sides by 5

• Subtract 6 from both sides then multiply both sides by 5

• Subtract 6 from both sides then divide both sides by 5

Tags

CCSS.7.EE.B.4A

What is a 2-step problem?

• An equation where 2 steps are needed to solve it.

• An equation where only one step is needed to solve it.

• A problem with only one operation present.

• A problem where you find the square-root of a number.

Tags

CCSS.7.EE.B.4A

What was done to solve the equation?

• add 8 to both sides, then divide both sides by 5

• add 8 to both sides, then divide both sides by 40

• subtract 8 from both sides, then divide both sides by 5

• subtract 8 from both sides, then multiply both sides by 5

Tags

CCSS.HSA.REI.A.1