Given f(x) = (1.11)18 and the rate of change is 11% every day, how much time has passed?
Exponential Word Problems Find the Decay or Growth

Quiz
•
Mathematics
•
9th Grade
•
Hard
Anthony Clark
FREE Resource
11 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
11 days
18 days
1.11 times 18 days
Underterminable
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Given f(x) = (1.0023)36 and the rate of change is 0.23% every hour, how many minutes have passed?
36
60
2160
3600
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The population in Haywardsville is decreasing at a rate of 2.5% per year. If the population in 2000 was 28,000, what will be the expected population in 2015 if this rate of decrease continues? (Verbal Question: How do we know this is growth or decay?)
19,153
19,285
18,956
19,172
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The population of a small town is 1600 and is increasing at a rate of 3% per year. Write an exponential function to model this situation. Then find the population of the town after 10 years. (Verbal Question: How do we know this is growth or decay?)
f(t) = 1600(1.03)t; 2,150 people
f(t) = 1600(0.97)t; 1,738 people
f(t) = 1600(1.03)t; 2,128 people
f(t) = 1600(0.97)t; 1,819 people
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The value of a book is $58 and depreciates at a rate of 7% per year. Write an exponential function to find the value of the book after 8 years. (Verbal Question: How do we know this is growth or decay?)
f(t) = 58(0.93)t; $32.46
f(t) = 58(1.07)t; $76.32
f(t) = 58(0.93)t; $34.26
f(t) = 58(1.07)t; $73.62
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Given the function f(x) = 1.07x, how do you know this is an exponential function?
Because the variable is in the exponent
Because the base has a decimal in it
Because f(x) is there
Because my teacher told me
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Write an exponential function to model the situation. Then solve. The cost of tuition at a college is $12,000 and is increasing at a rate of 6% per year. Which equations represents this situation?
C(t) = 1.06(12000)t
C(t) = 12000(.06)t
C(t) = 12000(.06)t
C(t) = 12000(1.06)t
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