Bisectors of Angles

Which Theorem allows us to say that ∡DBA=∡DBC

• Angle Bisector Theorem

• The converse of the Angle Bisector Theorem

• Perpendicular Bisector Theorem

• The converse of the Perpendicular Bisector Theorem

Tags

CCSS.HSG.CO.C.9

Find the measure of XW

Tags

CCSS.HSG.CO.C.9

Find the measure of the segment LP

• 3.5

• 9

• 2

• 1

Tags

CCSS.HSG.CO.C.10

Find the measure of segment CP

• 8

• 10

• 5

• 2

Tags

CCSS.HSG.CO.C.10

Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰ 
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
Step 6: m∠2 = 15⁰
Step 7: m∠1 = m∠2
What is the justification for Step 7?

• Subtraction property of equality

• Transitive property of equality

• Addition property of equality

• Definition of congruent angles

Tags

CCSS.HSG.SRT.B.5

Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰ 
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
Step 6: m∠2 = 15⁰
What is the justification for Step 6?

• Subtraction property of equality

• Substitution

• Addition property of equality

• Definition of congruent angles

Tags

CCSS.HSG.SRT.B.5

Given: m∠LAN = 30⁰ , m∠1 = 15⁰
Prove: AM bisects ∠LAN
Step 1: m∠LAN = 30⁰ 
Step 2: m∠1 + m∠2 = m∠LAN
Step 3: m∠1 + m∠2 = 30⁰
Step 4: m∠1 = 15⁰
Step 5: 15⁰ + m∠2 = 30⁰
Step 6: m∠2 = 15⁰
Step 7: m∠1 = m∠2
Step 8: ∠1 ≅ ∠2
Step 9: AM bisects ∠LAN
What is the justification for Step 9?

• Symmetric property of congruence

• Definition of angle bisector

• Addition property of equality

• Definition of congruent angles

Tags

CCSS.HSG.CO.C.9

Angle JHG measures 161.

• m∠GHK=80.5,

  m∠KHJ=161

• m∠GHK=161,

  m∠KHJ=80.5

• m∠GHK=80.5,

  m∠KHJ=80.5

• m∠GHK=161,

  m∠KHJ=161

Tags

CCSS.HSG.CO.C.9

Find the measure of segment QM

• 22

• 4

• 14

• 12

Tags

CCSS.HSG.CO.C.11

if Q is the incenter of ∆JLN, find JQ

• 19

• 22.1

• 18.8

• 15.8

Tags

CCSS.HSG.C.A.3