Algebra Math Word Problems

How old am I if 500 reduced by 5 times my age is 450?

• 350

• 4.5

• 10

• 5

Tags

CCSS.7.EE.B.4A

You had $23 to spend on four avocados. After buying them you had $11. How much did each avocado cost?

• $3

• $3.50

• $2.3

• $2

Tags

CCSS.7.EE.B.3

The sum of three consecutive numbers is 72. What is the mean of these 3 numbers?

• 22

• 23

• 24

• 25

Tags

CCSS.8.EE.C.7B

Nick had $24 to spend on seven pencils. After buying them he had $10. How much did each pencil cost?

• $1

• $2

• $3

• $4

Tags

CCSS.3.OA.D.8

The sum of three consecutive even numbers is 48. What is the number in the middle of the other two numbers?

• 15

• 16

• 17

• 18

Tags

CCSS.8.EE.C.7B

24 students in a class took an algebra test. If 18 students passed the test, what percent do not pass?
*HINT* Find out how many did not pass the class before you start! 

• 25%

• 75%

• 75 students

• 24 students

A large pizza at Palanzio’s Pizzeria costs $6.80 plus $0.90 for each topping. The cost of a large cheese pizza at Guido’s Pizza is $7.30 plus $0.65 for each topping. Which system of equations could be used to find the number of toppings when both companies cost the same amount?

• y = 6.80 + .65x
  y=7.30+.90x

• x + y = 6.80
  x + y = 7.30

• y = 6.80+.90x
  y = 7.30 + .65x

• y + .90x = 6.80
  y + .65x = 7.30

Tags

CCSS.8.EE.C.8C

At a college bookstore, Carla purchased a math textbook and a novel that cost a total of $54, not including tax. If the price of the math textbook, t, is $8 more than 3 times the price of the novel, n, which system of linear equations could be used to determine the price of each book?

• t + n = 54
  t = 3n + 8

• t + n = 54
  n = 3t + 8

• t + n = 54
  t = 3n - 8

• t + n = 8
  t = 3n + 54

Tags

CCSS.HSA.CED.A.3

The sum of Mr. Micklow and Ms. Craft's age is 55.  The difference is 3.  
Solve:
x + y = 55
x - y = 3

• (26, 23)

• (26, 29)

• (29, 26)

• (29, 32)

Tags

CCSS.8.EE.C.8C

The difference of a and b is 3. The sum of a and b is 13. Find the values of a and b.

• a = 7

  b = 10

• a = 8

  b = 5

• a = 10

  b = 13

• a = 6.5

  b = 2

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6