Solving Log on Both Sides

Solve log₉ (x - 4) + log₉ (x + 1) = log₉ (x + 5) + log₉ (x - 6)

• 17/2

• -9/16

• 13

• -8

log₅(4x-7)=log₅(x+5)

• 3

• 12

• 4

• 7

log₄(3x-1)=log₄(2x+3)

• 4

• 3

• 1

• 8

• log(x) + log(z) + 4log(y)
• 3log(x) − log(z) − 4log(y)
• 3log(x) + log(z) + 4log(y)
• log(x) − 4log(z) − 3log(y)

What would be the possible first step solving the equation log₂(x+3)=4

• Divide both sides by log₂

• Switch to exponent form

• Multiply both sides by log₂

• Modify the RHS to contain log₂

log₈(4x+4)=2

• 15

• 12

• 10

• 3

Convert 6^(x+2)=216 to logarithmic form

• log₂₁₆(x+2)=6

• log₆(x+2)=216

• log₆(216)=x+2

• log_(x+2)(216)=6

log₆-4x - log₆5=log₆70

• 149

• -16/3

• -175/2

• -47/5

• 175/2

(2x-1)log9 = (3x+1)log(3)

• 5

• 0

• 1

• 3

log₂(x+3)=4

• 16

• 13

• 3

• 10