An object in launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. Its height is represented by the equation
s(t) = –16t2 + 64t + 80.
What will be the object's maximum height?
Quadratic Applications Problems

Quiz
•
Mathematics
•
9th Grade
•
Hard
Anthony Clark
FREE Resource
19 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
2 ft
80 ft
144 ft
64 ft
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The function f(t) = -5t2+20t + 60 models the approximate height of an object t seconds after it is launched. How many seconds does it take the object to hit the ground?
4 seconds
-2 seconds
6 seconds
9 seconds
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
If a toy rocket is launched vertically upward from ground level with an initial velocity of 128 feet per second, then its height h after t seconds is given by the equation
h(t) = -16t2 +128t
When will the object reach its maximum height?
4 ft
0 seconds
0 ft
4 seconds
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
If I want to see the initial height of an object, I should _____________.
Substitute x = 0 into the equation and evaluate.
Use x = (-b /2a) as my answer.
Find the y-coordinate of the vertex.
Set my equation = 0 and solve.
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The function f(t) = -5t2+20t + 60 models the approximate height of an object t seconds after it is launched. How many seconds does it take the object to hit the ground?
4 seconds
-2 seconds
6 seconds
9 seconds
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A soccer ball is kicked from the ground with an initial upward velocity of 90 feet per second. The equation h=-16t2 + 90t gives the height h of the ball after t seconds.
What is the maximum height of the ball?
126.56 ft
5.625 sec
2.81 sec
90 ft
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A soccer ball is kicked from the ground with an initial upward velocity of 90 feet per second. The equation h=-16t2 + 90t gives the height h of the ball after t seconds.
How many seconds will it take the ball to hit the ground?
126.56 ft
5.625 sec
2.81 sec
0 ft
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