Solving Systems Substitution Y=

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve for x and y
y = 2x + 1
y = 4x - 1

• (1,3)

• (-1,-3)

• (-1,3)

• (3,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• (1, -1)

• (1, 1)

• (-1, 1)

• (-1, -1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve using substitution. Does the system have one, none or infinite solutions?

8x + 4y = 12

y = -2x + 3

• (0,3)

• (3,0)

• No solution(parallel lines)

• Infinitely many solutions

Tags

CCSS.8.EE.C.8B

What is the solution to this system? Solve by substitution.
y= 4x + 3
2x - 3y = 21

• (3,-9)

• (-3,-9)

• (-3,9)

• (0,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

The solution to the system of equations y = 2x + 1 and y = 4x - 1 is (a)   .

• (1,3)

• (0,0)

• (2,5)

• (3,7)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following systems of equations using substitution:

2y + x = -15

x = 3y

• (-3,-9)

• (-9,-3)

• (-3,9)

• (9,-3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve this system using substitution

y = 3x - 5

2x + 4y = -6

• (1, -2)

• (2, -2)

• (1, 2)

• Why have you done this?

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6