Solving Exponentials with Base

Given the following log equation, what would be the equivalent exponential equation?

• 8² = 3

• 3² = 8

• 2³ = 8

• 8³ = 2

If 3^x = 9^y, which of the following statements is TRUE?

• 27 = xy

• 3x = 9y

• x = 2y

• 2x = y

Solve 3³ = 3^{4x + 2}

• x = ¼

• x = -¼

• x = ½

• x = -½

Solve for x:
5^2x = 5^-x

• 0

• -6

• 8

• 1

8^3x+3 = 8⁶

• x=28

• x=3

• x=1

• x=12

How would you write 125 as an exponential with base 5?

How would you write 64 as an exponential with base 2?

Solve for x:
4^2x + 1 = 17

• x = 1

• x = -1

• x = 2

• x = -2

log_x1000=3

• 1

• 10

• 30

• 3

Change to Logarithmic Form:
5³ = 125

• log ₅ 125 = 3

• log ₃ 125 = 5

• log ₅ 3 =125

• log₁₂₅ 3 = 5