Extraneous Solutions of Radical Equations

Solve the radical equation. Check for extraneous solutions.

2 + (√3y - 5) = 10

y = (a)  

Tags

CCSS.HSA.REI.A.2

Solve.  Remember to check for extraneous solutions. 

• {-3}

• {6}

• {-5,6}

• {-5}

Tags

CCSS.HSA.REI.A.2

Solve and check your solution(s).

• x = 1

• x = 9

• x = all real solutions

• x = 9, 1

Tags

CCSS.HSA.REI.A.2

Solve.

• 8

• -8

• 0

• no solution

Tags

CCSS.HSA.REI.A.2

What is the first step to solving Radical Equations?

• Check for extraneous solutions.

• Raise each side of the equation to the power of the index.

• Isolate the radical on one side of equations.

• Solve the remaining equation.

• Convert from radical form to rational exponent form

Tags

CCSS.HSA.REI.A.2

The extraneous solution of the equation is...

• −3

• −5

• −6

• −10

Tags

CCSS.HSA.REI.A.2

Solve.

• no solution

• 6

• 3

• 4

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CCSS.HSA.REI.A.2

• 5

• 33

• 85

• 21

Tags

CCSS.HSA.REI.A.2

• 4
• 4, -1
• -1
• -4

Tags

CCSS.HSA.REI.A.2

This equation has...

• two positive solutions

• one positive solution and one negative extraneous solution

• one positive solution and one negative solution

• one negative solution and one negative extraneous solution

Tags

CCSS.HSA.REI.A.2