
Central, Inscribed, and Circumscribed Angles
Authored by Anthony Clark
Mathematics
10th Grade
CCSS covered

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15 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Identify the angle highlighted in blue.
Center of the circle
minor arc
Central angle
Inscribed angle
Tags
CCSS.HSG.C.A.2
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What formula would you use to find m<A?
angle = 1/2 (arc + arc)
angle = 1/2 (arc - arc)
angle = 1/2(arc)
circumscribed angle = 180 - central angle
Answer explanation
<A is an inscribed angle.
angle = 1/2(arc)
Tags
CCSS.HSG.C.A.2
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What formula would you use to find m<1?
angle = 1/2 (arc + arc)
angle = 1/2 (arc - arc)
angle = 1/2(arc)
circumscribed angle = 180 - central angle
Answer explanation
<1 is created from the tangent line, m, and chord AB.
angle = 1/2(intercepted arc)
Tags
CCSS.HSG.C.A.2
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What formula would you use to find m<x?
angle = 1/2 (arc + arc)
angle = 1/2 (arc - arc)
angle = 1/2(arc)
circumscribed angle = 180 - central angle
Answer explanation
<x is created from the secants that cross INSIDE the circle.
angle = 1/2 (arc + arc)
Tags
CCSS.HSG.C.A.2
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What formula would you use to find m<x?
angle = 1/2 (arc + arc)
angle = 1/2 (arc - arc)
angle = 1/2(arc)
circumscribed angle = 180 - central angle
Answer explanation
<x is created from the secants that cross OUTSIDE the circle.
angle = 1/2 (larger arc - smaller arc)
Tags
CCSS.HSG.C.A.2
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The sides of circumscribed angles are _________ to the circle.
<B is the circumscribed angle.
tangent
secant
parallel
perpendicular
Answer explanation
tangent = touches the circle at one point
Tags
CCSS.8.G.A.5
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What formula would you use to find m<x?
angle = 1/2 (arc + arc)
angle = 1/2 (arc - arc)
angle = 1/2(arc)
circumscribed angle = 180 - central angle
Answer explanation
<x is created from the two tangent lines. It is a circumscribed angle.
circumscribed angle = 180 - central angle
Tags
CCSS.HSG.C.A.2
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