Solving Polynomial Equations by Factoring

Solve the equation by factoring:

Tags

CCSS.HSA-REI.B.4B

Solve by Factoring 8x^3-125=0

Tags

CCSS.HSA.APR.B.3

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(2x - 1)(x + 4) = 0

• { 1/2, -4 }

•  { 1/2, 4 }

• { 2, -4 }

• { -2, 4 }

Tags

CCSS.HSA-REI.B.4B

Solve (x²-9) = 0

• x = 9

• x = 9, -9

• x = 3, -3

• x = 3

Tags

CCSS.8.EE.A.2

What are two solutions to the polynomial:
x²+14x=0

• x=0, x= 14

• x=-14

• x= 1, x =10

• x= -14, x = 0 

Tags

CCSS.HSA-REI.B.4B

Factor this difference of cubes:
x³ - 343

• (x + 7) (x² - 7x + 49)

• (x² + 1) (x - 343)

• (x - 7) (x² + 7x + 49)

• (x² - 343) (x + 1)

Tags

CCSS.HSA.APR.C.4

Factor:   x³ + 1

• (x + 1)³

• (x+1)(x² - x + 1)

• (x - 1) (x² + x - 1)

• (x + 1)(x² - 2x + 1)

Tags

CCSS.HSA.APR.C.4