Quadratic Equations Directrix and Focus

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(x+3)² = 4(y+5) What is the equation of the directrix?

• x = 4

• x = 2

• y = -4

• y = -6

(y-4)² = -8(x+1) What are the coordinates for the focus? #4

• (1,4)

• (-1,6)

• (-1,2)

• (-3,4)

Given this directrix and vertex, what would the equation of the parabola be?

• (y-2)² = 12(x-1)

• (y-2)² = 6(x-1)

• (x-1)² = 12(y-2)

• (x-1)² = 6(y-2)

(y-4)² = -8(x+1)
What are the coordinates for the focus?

• (1,4)

• (-1,6)

• (-1,2)

• (-3,4)

(x+3)² = 4(y+5)
What is the equation of the directrix?

• x = 4

• x = 2

• y = -4

• y = -6

Find the vertex, focus, and directrix of the parabola: x² = 28y

• Vertex: (0, 0) Focus: (0,7) Directrix: y=-7

• Vertex: (0, 0) Focus: (7,0) Directrix: y=7

• Vertex: (0, 0) Focus: (0,-7) Directrix: x=-7

• Vertex: (0, 0) Focus: (7, 0) Directrix: x=7

Write the equation and graph the parabola from the following information.

Vertex: (0,0), Focus: (0,3)