Is the point (3, 1) a solution for the following inequality? Choose the best answer that has the best explanation.

No because it is located on the line and the line is dotted.

Yes because it is located in the shaded region.

Yes because it is located on the line.

No because it is in the shaded region.

Are the points on the boundary line part of the solution set or not?

Yes, they are part of the solution set

No, they are NOT part of the solution set

Which of the following sets of linear inequalities defines the shaded region in Diagram 3?

y ≥ 4 − x, y + 2x ≤ 8 and y < 4

y ≥ 4 − x, y + 2x ≥ 8 and y < 4

y ≤ 4 − x, y + 2x ≥ 8 and y > 4

y ≤ 4 − x, y + 2x ≤ 8 and y > 4

Are the points on the boundary line part of the solution set?

Yes, they are part of the solution set

No, they are NOT part of the solution set

Is the point (1, 2) a solution for the following inequality?

Yes, it is located in the shaded region.

No, it is located on the line and the line is dotted.

No, it is located in the shaded region.

Yes, it is located on the line.

cot ⁡ A cot ⁡ B − 1 cot ⁡ A + cot ⁡ B \frac{\cot A\cot B-1}{\cot A+\cot B} cot A + cot B cot A cot B − 1

cot ⁡ A cot ⁡ B + 1 cot ⁡ A − cot ⁡ B \frac{\cot A\cot B+1}{\cot A-\cot B} cot A − cot B cot A cot B + 1

cot ⁡ A cot ⁡ B − 1 cot ⁡ B − cot ⁡ A \frac{\cot A\cot B-1}{\cot B-\cot A} cot B − cot A cot A cot B − 1

2 cos ⁡ ( 3 A + 3 B 2 ) cos ⁡ ( 3 A − 3 B 2 ) = 2\cos\left(\frac{3A+3B}{2}\right)\cos\left(\frac{3A-3B}{2}\right)\ = 2 cos ( 2 3 A + 3 B ) cos ( 2 3 A − 3 B ) =

cos ⁡ 3 A + cos ⁡ 3 B \cos3A+\cos3B cos 3 A + cos 3 B

sin ⁡ 3 A − sin ⁡ 3 B \sin3A-\sin3B sin 3 A − sin 3 B

cos ⁡ ( 3 A + 3 B ) \cos\left(3A+3B\right) cos ( 3 A + 3 B )

sin ⁡ ( 3 A − 3 B ) \sin\left(3A-3B\right) sin ( 3 A − 3 B )

2 cos ⁡ ( A + B 2 ) sin ⁡ ( A − B 2 ) = 2\cos\left(\frac{A+B}{2}\right)\sin\left(\frac{A-B}{2}\right)= 2 cos ( 2 A + B ) sin ( 2 A − B ) =

sin ⁡ A − sin ⁡ B \sin A-\sin B sin A − sin B

cos ⁡ A − cos ⁡ B \cos A-\cos B cos A − cos B

sin ⁡ ( A − B ) \sin\left(A-B\right) sin ( A − B )

cos ⁡ ( A − B ) \cos\left(A-B\right) cos ( A − B )

sec ⁡ ( 270 ° − θ ) = \sec\left(270\degree-\theta\right)\ = sec ( 2 7 0 ° − θ ) =

− cosec ⁡ θ -\operatorname{cosec}\theta − c o s e c θ

cosec ⁡ θ \operatorname{cosec}\theta c o s e c θ

− sec ⁡ θ -\sec\theta − sec θ

sin ⁡ ( 7 π 4 ) = \sin\left(\frac{7\pi}{4}\right)\ = sin ( 4 7 π ) =

− 1 2 -\frac{1}{\sqrt{2}} − 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

− 3 2 \frac{-\sqrt{3}}{2} 2 − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

If P( -4) = 0, which of the following statements is true about P(x) ?

P(x) = 0, has four negative roots

1. If P( -4) = 0, which of the following statements is true about P(x) ?

P(x) = 0, has four negative roots

Optional Math(Anamika)

Authored by Aanamika Rimal

Mathematics

10th Grade

CCSS covered

Used 2+ times

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70 questions

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MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Elizabeth is flying a kite, which gets caught in the top of a tree. Use the diagram to estimate the height of the tree.

63.6 ft

1.59 ft

74.2 ft

86.9 ft

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Solve for x. Round to the nearest tenth.

74.9

3.6

63.5

54.1

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Find h₂

16.73 ft

22.51 ft

18.59 ft

20.79 ft

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Solve for the missing angle.

0.053

36.9

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Choose the correct ratio.

$\sin\left(37\right)=\frac{x}{14}$

$\cos(37)=\frac{x}{14}$

$\tan(37)=\frac{x}{14}$

$\sin(37)=\frac{14}{x}$

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Which inequality is represented by the following graph:

x < -8

x > -8

x ≥ -8

x ≤ -8

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Which inequality is represented by the following graph:

x > 9

x < 9

x ≥ 9

x ≤ 9

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Optional Math(Anamika)