Simple Harmonic Motion Period

A force of  30 N stretches a very light ideal spring 0.73 m from equilibrium. What is the force constant (spring constant) of the spring?

• 41 N/m
• 22 N/m
• 34 N/m
• 46 N/m

A pair of trapeze performers at the circus is swinging from ropes attached to a large elevated platform. Suppose that the performers can be treated as a simple pendulum with a length of 16 m. Determine the period for one complete back and forth cycle.

• 2 sec
• 12 sec
• 8 sec
• 10 sec

A pendulum is 0.75 meters long and has a period of 4.17 seconds. The Pendulum is on an unknown planet.  What is the gravity of the Unknown Planet?

• 9.8
• 3.4
• 1.7
• Greater than 9.8

Tags

NGSS.HS-PS2-4

If the length of a simple pendulum is doubled, its period will: 

• halve 
• increase by a factor of sqrt(2) 
• decrease by a factor of sqrt(2)
• double 

From the graph ,the spring constant is.

• 4.5 m

• 15 N

• 20 N/m

• 200 N/m

A net force of 430 N acts to stretch an extension spring.  How far will the spring stretch if its spring constant is 700 N/m?

• 43.9
• 0.307 m
• 1.63 m
• 0.614 m

What force should be applied to compress a spring by 0.013 m if its spring constant is k = 1900 N/m?

• 1880 N
• 24.7 N
• 1900 N
• 0.127 N

What is the equation for frequency?

• f = t/n
• f = 1/T
• f = 2 T

Tags

NGSS.HS-PS4-1

A mass-spring system can oscillate with simple harmonic motion because a compressed or stretched spring has which kind of energy?

• kinetic
• mechanical
• gravitational potential
• elastic potential

For a system in simple harmonic motion, which of the following is the time required to complete a cycle of motion?

• amplitude
• period
• frequency
• revolution

Tags

NGSS.HS-PS4-1