(0901) Avogadro’s number is:

• 6.02 x 10²²

• 6

• 6.02 x 10²³

• 3.01 x 10²³

(0901) Which conversion would you use if you need to convert from MOLES to particles?

• $\frac{1\ mole}{6.02\ x\ 10^{23}particles}$

• $\frac{6.02\ x\ 10^{23}moles}{1\ particle}$

• $\frac{6.02\ x\ 10^{23}particles}{1\ mole}$

• $\frac{1\ particle}{6.02\ x\ 10^{23}\ moles}$

(0902) The mass of one mole of a substance is called...

• molecular mass

• mole constant

• molar mass

• atomic weight

(0903) Suzie wants to know the mass of 1.55 moles of nitrogen trichloride. How do you set up the problem?

• $1.55\ mole\ NCl_3\ \times\ \frac{1\ mole}{molar\ mass\ of\ NCl_3\ \left(g\right)}=$

• $1.55\ mole\ NCl_3\ \times\ \frac{molar\ mass\ of\ NCl_3\ \left(g\right)}{1\ mole}=$

• $\ 1\ mole\ \times\ \frac{1.55\ mole\ NCl_3}{molar\ mass\ of\ NCl_3\left(g\right)}=$

• $\ molar\ mass\ of\ NCl_3\left(g\right)\ \times\ \frac{1\ mole}{1.55\ mole\ NCl_3}=$

2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O

Ethane (C₂H₆) combusts in the above reaction. What is the mole ratio of ethane to oxygen gas?

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• 

2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O

Ethane (C₂H₆) combusts in the above reaction. What is the mole ratio of carbon dioxide to water?

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2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O

A problem asks how many moles of oxygen gas are needed to react completely with 6 moles of ethane (C₂H₆). What is the first step in setting up the problem?

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• 
• 
• 

2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O

A problem asks how many moles of oxygen gas are needed to react completely with 6 moles of ethane (C₂H₆). What is the second step in setting up the problem?

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• 
• 
• 

2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O

A problem asks how many moles of oxygen gas are needed to react completely with 6 moles of ethane (C₂H₆). What is the final answer for this problem?

• 13 mol C₂H₆

• 3 mol O₂

• 21 mol O₂

• 42 mol O₂