
Science
10th Grade
moles = conc x vol covered

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15 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
H2SO4 + 2NaOH --> Na2SO4 + 2H2O
To 2 dp, what volume of 2.0 mol/dm3 H2SO4 solution will neutralise
36.20cm3 of 2.0 mol/dm3 NaOH solution?
36.20cm3
18.10cm3
0.04cm3
0.02cm3
Answer explanation
Each mole of H2SO4 neutralises 2 moles of NaOH
Tags
moles = conc x vol
reacting ratio
vol = moles / conc
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the concentration of the NaOH solution, if 20.0cm3 of it is neutralised by 25.00cm3 of 0.1 mol/dm3 H2SO4 solution?
0.75 mol/dm3
1.0 mol/dm3
1.25 mol/dm3
0.25 mol/dm3
Answer explanation
Each mole of H2SO4 reacts with 2 moles of NaOH
Tags
reacting ratio
moles = conc x vol
conc = moles / vol
acids as monoprotic/diprotic/triprotic
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the concentration of the H2SO4 solution, if 40.0cm3 of it is neutralised by 20.00cm3 of 0.1 mol/dm3 NaOH solution?
0.025 mol/dm3
4.00 x 10-5 mol/dm3
0.03 mol/dm3
25.00 mol/dm3
Tags
reacting ratio
moles = conc x vol
conc = moles / vol
acids as monoprotic/diprotic/triprotic
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the concentration of the NaOH solution, if 36.00cm3 of it neutralises 25.0cm3 of 2.4mol/dm3 H3PO4 solution?
2.16 x 10-3 mol/dm3
4.5 x 10-3 mol/dm3
5.0 mol/dm3
7.2 x 10-4 mol/dm3
Answer explanation
Each mole of H3PO4 neutralises 3 moles of NaOH
Tags
reacting ratio
moles = conc x vol
conc = moles / vol
acids as monoprotic/diprotic/triprotic
5.
OPEN ENDED QUESTION
1 min • 1 pt
Write a balanced chemical equation for the reaction of the following acid and base:
___ H2SO4 + ___KOH -->
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6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
For the acid-base titration combination of NaOH with 0.79 mol HCl, find the number of moles of NaOH that would be the chemically equivalent amount of HCl.
0.79 mol
1.6 mol
0.38 mol
3.2 mol
Tags
NGSS.HS-PS1-7
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
If it takes 50 mL of 0.5 M Ca(OH)2 to neutralize 125 mL of sulfuric acid, what is the concentration of the acid?
0.2 M
5 M
0.5 M
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