Explore Variables: Distributive Property Word Problems

1. Sarah has 4 bags of apples. Each bag contains 'x' apples. Write an equation to represent the total number of apples Sarah has using the distributive property.

• 4x

• 2x

• x+4

• 4+x

Tags

CCSS.6.EE.A.3

2. A toy costs $15. If you buy 'y' toys, how can you express the total cost using the distributive property?

• $15 + y

• $15y + 15

• 15y + 1

• 15y

Tags

CCSS.6.EE.A.3

3. A farmer has 3 fields. Each field has 'z' rows of corn. Write an equation to show the total number of rows of corn using the distributive property.

• z + z + z

• 3 + z

• 3 - z

• 3 * z

Tags

CCSS.6.EE.A.3

4. Emily is making gift bags. She puts 5 candies in each bag. If she makes 'b' bags, how can you express the total number of candies using the distributive property?

• b - 5

• 5 + b

• 5 / b

• 5 * b

Tags

CCSS.6.EE.A.3

5. A book costs $12. If you buy 'n' books, write an equation using the distributive property to find the total cost.

• Total cost = 12 + n

• Total cost = n - 12

• Total cost = 12 * n

• Total cost = 12 / n

Tags

CCSS.8.EE.C.7B

6. There are 6 packs of markers. Each pack contains 'm' markers. Write an equation to represent the total number of markers using the distributive property.

• 6 - m

• 6 * m

• 6 / m

• m + 6

Tags

CCSS.6.EE.A.3

7. A pizza has 8 slices. If 'p' pizzas are ordered, how can you express the total number of slices using the distributive property?

• 8 + p

• p * 8 + 1

• 8 * p

• p - 8

Tags

CCSS.6.EE.A.3

8. A school has 4 classes. Each class has 'c' students. Write an equation to show the total number of students using the distributive property.

• 8c

• 4c

• c+4

• 2c

Tags

CCSS.6.EE.A.3

9. A box contains 10 toys. If you have 't' boxes, how can you express the total number of toys using the distributive property?

• 10 + t^2

• t + 10

• 5t

• 10t

Tags

CCSS.6.EE.A.3

10. A pack of gum costs $2. If you buy 'g' packs, write an equation using the distributive property to find the total cost.

• Total Cost = g + 2

• Total Cost = 2 + g

• Total Cost = 2g + 1

• Total Cost = 2g

Tags

CCSS.8.EE.C.7B