Search Header Logo

Unit 6 Lesson 5-7 QPC Prep Projectile Motion and Quadratics

Authored by Wayground Content

Mathematics

9th Grade

Unit 6 Lesson 5-7 QPC Prep Projectile Motion and Quadratics
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

A ball is thrown into the air with an upward velocity of 64 ft/s. Its height, h, after t seconds is given by the function
 h = -16t2 + 64t + 960.
When did the ball hit the ground?

10 seconds
2 seconds
5 seconds
7 seconds

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Mrs. Martone's 7th grade science class built and launched rockets. The graph below shows the height, in feet, over time, in seconds, of a student's rocket. Use the graph to answer the questions below. How long was the rocket in the air?

1 second

7 seconds

14 seconds

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

A company graphed the revenue (profit) based on selling price of their item. If the items were $62, how much revenue would they have?

$0

$31.80

$62

$2,528,100

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

A ball is hit into the air with an initial velocity of 100 ft/s. Its height, h, after t seconds is given by the function

h = -16t2 + 100t + 5

How many seconds did it take for the ball to reach its maximum height?

3.654 seconds

2.451 seconds

161.25 seconds

3.125 seconds

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

A ball is thrown into the air with an initial velocity of 100 ft/s. Its height, h, after t seconds is given by the function

h = -16t2 + 100t + 5.

When did the ball hit the ground?

6.300 seconds

11.251 seconds

5.369 seconds

7.458 seconds

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

The height of an object thrown into the air can be modeled by the formula h(t) = -16t2 + 70t + 95, where h(t) is in feet after t seconds.
What is the height of the object after 5 seconds?

95 feet
45 feet
70 feet
171.56 feet

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Given the revenue function R(x) = -500x2+8000x+100. How can you find the max revenue?

Find the Vertex, then the max revenue will be the x value of the vertex.

Find the Vertex, then the max revenue will be the y value of the vertex.

The max revenue is the same as the y-intercept

Find the zeros and the larger value is the max revenue.

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?