Unit 6 Lesson 5-7 QPC Prep Projectile Motion and Quadratics

Unit 6 Lesson 5-7 QPC Prep Projectile Motion and Quadratics

9th Grade

20 Qs

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Unit 6 Lesson 5-7 QPC Prep Projectile Motion and Quadratics

Unit 6 Lesson 5-7 QPC Prep Projectile Motion and Quadratics

Assessment

Quiz

Mathematics

9th Grade

Practice Problem

Hard

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20 questions

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1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

A ball is thrown into the air with an upward velocity of 64 ft/s. Its height, h, after t seconds is given by the function
 h = -16t2 + 64t + 960.
When did the ball hit the ground?

10 seconds
2 seconds
5 seconds
7 seconds

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Mrs. Martone's 7th grade science class built and launched rockets. The graph below shows the height, in feet, over time, in seconds, of a student's rocket. Use the graph to answer the questions below. How long was the rocket in the air?

1 second

7 seconds

14 seconds

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

A company graphed the revenue (profit) based on selling price of their item. If the items were $62, how much revenue would they have?

$0

$31.80

$62

$2,528,100

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

A ball is hit into the air with an initial velocity of 100 ft/s. Its height, h, after t seconds is given by the function

h = -16t2 + 100t + 5

How many seconds did it take for the ball to reach its maximum height?

3.654 seconds

2.451 seconds

161.25 seconds

3.125 seconds

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

A ball is thrown into the air with an initial velocity of 100 ft/s. Its height, h, after t seconds is given by the function

h = -16t2 + 100t + 5.

When did the ball hit the ground?

6.300 seconds

11.251 seconds

5.369 seconds

7.458 seconds

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

The height of an object thrown into the air can be modeled by the formula h(t) = -16t2 + 70t + 95, where h(t) is in feet after t seconds.
What is the height of the object after 5 seconds?

95 feet
45 feet
70 feet
171.56 feet

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Given the revenue function R(x) = -500x2+8000x+100. How can you find the max revenue?

Find the Vertex, then the max revenue will be the x value of the vertex.

Find the Vertex, then the max revenue will be the y value of the vertex.

The max revenue is the same as the y-intercept

Find the zeros and the larger value is the max revenue.

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