A sound wave is travelling through water.
What is a possible speed for the wave?
Single PX only set 2
Quiz
•
Physics
•
9th - 10th Grade
•
Hard
S Doran
Used 1+ times
FREE Resource
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
A sound wave is travelling through water.
What is a possible speed for the wave?
150 m/s
300 m/s
1500 m/s
5000 m/s
Answer explanation
Useful speed to recall - sound travels ~ 340 m/s in air, ~1500 m/s in water
2.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
A force F is applied to a spanner, as shown.
Which action increases the moment of F about the centre of the nut?
apply the force F to the end of the spanner handle
apply the force F parallel to the spanner handle
spray oil on the nut
use a shorter spanner
Answer explanation
Moment = force x perpendicular distance from the pivot to the line of action of the force
3.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Bats produce ultrasound waves to navigate.
What is a possible frequency range for these waves?
0–20 Hz
20 Hz–2000 Hz
2 kHz–20 kHz
20 kHz–120 kHz
Answer explanation
Ultrasound is sound with a frequency > 20 kHz
4.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
The diagram shows a transformer that has an output voltage of 12 V.
How many turns of wire are in the secondary coil?
12
20
50
20 000
Answer explanation
Ns = Np x Vs ÷ Vp
5.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
An athlete with mass 70 kg trains by performing press-ups with a load on his back. The diagram shows the perpendicular distances involved. The centre of mass of the athlete is CM and the centre of mass of the load he is carrying is CL. (An object's weight acts through its centre of mass)
The mass of the load is 6.0 kg. What is the upward force exerted by his two arms?
54 N
76 N
540 N
760 N
Answer explanation
anti clockwise moment about foot:
(0.9 m x 700 N) + (1.2 m x 60 N) = 702 Nm
clockwise moment about foot = ? N x 1.3 m
? = 702 Nm ÷ 1.3 m = 540 N
6.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Two people X and Y sit on a see-saw, as shown.
X weighs 400 N and sits 1.5 m from the pivot. pivot
The weight of the see-saw is 300 N and acts through the pivot.
When the see-saw is balanced, the pivot pushes up on the see-saw with a force of 900 N.
What is the weight of person Y and how far from the pivot is he sitting?
Weight of Y=200 N
Distance from pivot = 1.5 m
Weight of Y=200 N
Distance from pivot = 3.0 m
Weight of Y=400 N
Distance from pivot = 1.5 m
Weight of Y=400 N
Distance from pivot = 3.0 m
Answer explanation
Moment of X = 400 N x 1.5 m = 600 Nm
Moment of Y = 600 Nm = 200 N x 3m
(OR 400 N x 1.5m)
BUT: Total downward force = 900 N (to balance upward force) so Y's weight must be 200 N
7.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Air in a sealed syringe is slowly compressed by moving the piston. The temperature of the air stays the same.
Which statement about the air is correct?
The pressure of the air decreases because its molecules now travel more slowly.
The pressure of the air decreases because the area of the syringe walls is now smaller.
The pressure of the air increases because its molecules now hit the syringe walls more frequently.
The pressure of the air increases because its molecules now travel more quickly.
Answer explanation
In a closed system where the temperature stays the same, the pressure of a gas increases as the volume decreases.
The number of molecules and their average energy do not change. The force of each collision with the sides of the container (AT 90o TO THE SURFACE) stays the same BUT the number of frequency of collisions increases because the surface area of the container is smaller so the pressure increases.
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