RSA in Cryptography (Assignment 3 Part 1)

RSA in Cryptography (Assignment 3 Part 1)

Professional Development

25 Qs

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 RSA in Cryptography (Assignment 3 Part 1)

RSA in Cryptography (Assignment 3 Part 1)

Assessment

Quiz

Professional Development

Professional Development

Practice Problem

Medium

Created by

Geetha Chenpagapandian

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25 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does RSA stand for in cryptography?

Rivest-Smith-Adleman

Roberts-Shamir-Adleman

Rivest-Shamir-Alderman

Rivest-Shamir-Adleman

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Explain the basic principle of RSA encryption.

RSA encryption uses prime factorization to secure data through a pair of keys: a public key for encryption and a private key for decryption.

RSA encryption is based on the use of hash functions to secure data.

RSA encryption uses a single key for both encryption and decryption.

RSA encryption relies on symmetric key algorithms for security.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the key components needed to generate RSA keys?

Public key only

A single random number

Two large prime numbers, modulus, public exponent, private exponent

One small prime number

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the public key in RSA generated?

The public key in RSA is generated as the pair (e, n) where n = p * q and e is a chosen exponent coprime to (p-1)(q-1).

The public key is derived from the product of p and q without any exponent.

The public key is generated using only the value of p.

The public key consists of the values (d, n) where d is the private exponent.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of the private key in RSA?

The private key is used for encrypting messages.

The private key is used for signing messages.

The private key in RSA is used for decrypting messages.

The private key is used to generate public keys.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Provide an example of how to encrypt a message using RSA.

For example, if n = 55, e = 17, and the message m = 42, then c = 42^17 mod 55 = 8.

Using n = 77, e = 13, and m = 30, c = 30^13 mod 77 = 50.

To encrypt, simply reverse the message and add 3 to each character.

If n = 45, e = 5, and m = 10, then c = 10^5 mod 45 = 25.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the mathematical basis for RSA's security?

The difficulty of factoring large prime numbers.

The speed of data encryption algorithms.

The ease of multiplying small numbers.

The simplicity of addition and subtraction.

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