What is the domain of the for the following piecewise function?

( − ∞ , + ∞ ) \left(-\infty,\ +\infty\right) ( − ∞ , + ∞ )

[ − 6 , + ∞ ) \left[-6,\ +\infty\right) [ − 6 , + ∞ )

( − ∞ , − 5 ) ∪ [ − 3 , + ∞ ) \left(-\infty,-5\right)\cup\left[-3,\ +\infty\right) ( − ∞ , − 5 ) ∪ [ − 3 , + ∞ )

[ − 5 , 3 ) \left[-5,\ 3\right) [ − 5 , 3 )

What is the range for the following piecewise function?

[ − 6 , + ∞ ) \left[-6,\ +\infty\right) [ − 6 , + ∞ )

( − ∞ , − 5 ] \left(-\infty,\ -5\right] ( − ∞ , − 5 ]

[ − 3 , + ∞ ) \left[-3,\ +\infty\right) [ − 3 , + ∞ )

( − ∞ , + ∞ ) \left(-\infty,\ +\infty\right) ( − ∞ , + ∞ )

Evaluate f ( x ) f\left(x\right) f ( x ) for x = − 9 x=-9 x = − 9 and x = 5 x=5 x = 5

f ( − 9 ) = 15 , f ( 5 ) = 0 f\left(-9\right)=15,\ f\left(5\right)=0 f ( − 9 ) = 1 5 , f ( 5 ) = 0

f ( − 9 ) = 0 , f ( 5 ) = 15 f\left(-9\right)=0,\ f\left(5\right)=15 f ( − 9 ) = 0 , f ( 5 ) = 1 5

f ( − 9 ) = 0 , f ( 5 ) = − 6 f\left(-9\right)=0,\ f\left(5\right)=-6 f ( − 9 ) = 0 , f ( 5 ) = − 6

f ( − 9 ) = 15 , f ( 5 ) = − 6 f\left(-9\right)=15,\ f\left(5\right)=-6 f ( − 9 ) = 1 5 , f ( 5 ) = − 6

Select the correct domain for this piecewise function.

[ − 6 , 4 ] \left[-6,\ 4\right] [ − 6 , 4 ]

[ − 3 , 1 ] \left[-3,\ 1\right] [ − 3 , 1 ]

[ − 12 , 8 ] \left[-12,\ 8\right] [ − 1 2 , 8 ]

( − ∞ , + ∞ ) \left(-\infty,\ +\infty\right) ( − ∞ , + ∞ )

Select the correct range for this piecewise function.

[ − 3 , 1 ] \left[-3,\ 1\right] [ − 3 , 1 ]

( − ∞ , + ∞ ) \left(-\infty,\ +\infty\right) ( − ∞ , + ∞ )

[ − 12 , 8 ] \left[-12,\ 8\right] [ − 1 2 , 8 ]

[ − 6 , 4 ] \left[-6,\ 4\right] [ − 6 , 4 ]

Check all of the statements that are true

The domain of the piecewise function is ( − ∞ , ∞ ) \left(-\infty,\ \infty\right) ( − ∞ , ∞ )

The range of the piecewise function is [ − 2 ] ∪ [ 0 , ∞ ) \left[-2\right]\cup\left[0,\infty\right) [ − 2 ] ∪ [ 0 , ∞ )

The domain of the piecewise function is ( − ∞ , ∞ ) \left(-\infty,\infty\right) ( − ∞ , ∞ ) except 0 and 4

The range of the piecewise function is ( − 2 ) ∪ ( 0 , ∞ ] \left(-2\right)\cup\left(0,\infty\right] ( − 2 ) ∪ ( 0 , ∞ ]

Which equation is the equation of the graphed function?

g ( x ) = − 2 ∣ x + 3 ∣ + 3 g\left(x\right)\ =\ -2\left|x+3\right|+3 g ( x ) = − 2 ∣ x + 3 ∣ + 3

g ( x ) = − 2 ∣ x − 3 ∣ + 3 g\left(x\right)\ =\ -2\left|x-3\right|+3 g ( x ) = − 2 ∣ x − 3 ∣ + 3

g ( x ) = − ∣ x + 3 ∣ + 3 g\left(x\right)\ =\ -\left|x+3\right|+3 g ( x ) = − ∣ x + 3 ∣ + 3

g ( x ) = ∣ x + 3 ∣ + 3 g\left(x\right)\ =\ \left|x+3\right|+3 g ( x ) = ∣ x + 3 ∣ + 3

Choose the correct equation for the graph below.

y = − ∣ x − 4 ∣ − 3 y=-\left|x-4\right|-3 y = − ∣ x − 4 ∣ − 3

y = ∣ x − 4 ∣ − 3 y=\left|x-4\right|-3 y = ∣ x − 4 ∣ − 3

y = − ∣ x + 4 ∣ − 3 y=-\left|x+4\right|-3 y = − ∣ x + 4 ∣ − 3

y = − ∣ x + 4 ∣ + 3 y=-\left|x+4\right|+3 y = − ∣ x + 4 ∣ + 3

Write the equation for the given transformations. VS of 2, Right 6, Up 12

y = 2 x − 6 + 12 y=\frac{2}{x-6}+12 y = x − 6 2 + 1 2

y = 2 x − 12 + 6 y=\frac{2}{x-12}+6 y = x − 1 2 2 + 6

y = 2 x + 12 + 6 y=\frac{2}{x+12}+6 y = x + 1 2 2 + 6

y = 2 x + 6 + 12 y=\frac{2}{x+6}+12 y = x + 6 2 + 1 2

PreCal Test Review 3.4

Authored by Marita Harrell

Mathematics

11th Grade

Used 3+ times

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MULTIPLE CHOICE QUESTION

10 mins • 1 pt

Which piecewise function corresponds to this graph? (Take your time)

f(x) = { x if x < 4; -x+1 if x ≥ 4

f(x) = { x if x ≤ 4; -x+1 if x > 4

f(x) = { -x+1 if x < 4; x if x ≥ 4

f(x) = { -x+1 if x ≤ 4; x if x > 4

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

Using the pictured graph, what is f(-3)?

-3

-1

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

Which graph matches:
4-x for x<2
2x-6 for x>=2

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

What is g(7) if:

-17

-13

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

What is m(-3) if:

-3

0.5

-3.5

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

What are the domain restrictions for the green piece of this function?

-2 < x ≤ 1

-1 < x ≤ 0.5

x > -2

x ≤ 1

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

What are the domain restrictions for the middle piece of this function?

x ≥ 1

x ≥ 2

2 ≤ x < 6

1 ≤ x < 3

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PreCal Test Review 3.4