ZPP and FOILING Practice

(x + 4)(x + 7) = 0

• x = 4 and 7

• x = -4 and 7

• x = 4 and -7

• x = -4 and -7

Tags

CCSS.HSA-REI.B.4B

(x - 8)(x + 7) = 0

• x = 8 and 7

• x = 8 and -8

• x = 8 and -7

• x = -8 and 7

Tags

CCSS.HSA-REI.B.4B

(x + 5)(x - 4) = 0

• x = -5 and 4

• x = -5 and -4

• x = 5 and -4

• x = 5 and -4

Tags

CCSS.HSA-REI.B.4B

(x - 5)(x - 2) = 0

• x = -5 and 2

• x = 5 and 2

• x = 5 and -2

• x = -5 and -2

Tags

CCSS.HSA-REI.B.4B

(x + 3)(x + 4) = 0

• x = -3 and -4

• x = 3 and 4

• x = -3 and 4

• x = 3 and -4

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(2x - 1)(x + 4) = 0

• { 1/2, -4 }
•  { 1/2, 4 }
• { 2, -4 }
• { -2, 4 }

Tags

CCSS.HSA-REI.B.4B

• x=0

• x=5

• x=2

• x= -5

Tags

CCSS.6.EE.B.7

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B

 $\left(c+6\right)\left(c-7\right)=0$  

•  $c=-6,\ c=7$  

•  $c=6,\ c=-7$  

•  $c=6,\ c=7$  

•  $c=-6,\ c=-7$  

Tags

CCSS.HSA-REI.B.4B

 $\left(u-2\right)\left(u+8\right)=0$  

•  $u=2,\ u=-8$  

•  $u=-2,\ u=8$  

•  $u=2,\ u=8$  

•  $u=-2,\ u=-8$  

Tags

CCSS.HSA-REI.B.4B