Parametric Equations

What would the gradient of the tangent to the curve $$y=2x^2+1$$  at (2,9) be?

(a)  

Find the equation of the tangent at $$y\ =\ x^2+5x\ +6$$ at the point $$\left(-1,2\right)$$

Find the equation of the normal at $$y\ =\ x^2+5x\ +6$$ at the point $$\left(-1,2\right)$$

Find dy/dx

$$x=5\ t\ ^2+3\ ,\ y\ =\ 10\ t+4$$  

If $$x=e^{-t}$$  and  $$y=\cos\left(2t\right)$$  then $$\frac{dy}{dx}=$$  

Let's consider the parametric equations, In terms of t, find $$\frac{\text{d}y}{\text{d}x}$$

$$x=t^2+1$$

$$y=2t+3$$

Let's consider the parametric equations,

$$x=t^2+1$$ , $$y=2t+3$$ , $$\frac{\text{d}y}{\text{d}y}=\frac{1}{t}$$

At the point a, find the equation of the tangent in the form $$y-y_1=m\left(x-x_1\right)$$