Exploring Newton's Laws of Motion

A car is moving with a constant velocity. According to Newton's first law, what can be inferred about the forces acting on the car?

• The net force on the car is zero.

• There is a net force acting in the direction of motion.

• The net force is acting opposite to the direction of motion.

• The car is accelerating.

A 5 kg object is subjected to a net force of 20 N. What is the acceleration of the object?

• 2 m/s²

• 4 m/s²

• 5 m/s²

• 10 m/s²

Which of the following scenarios best illustrates Newton's first law of motion?

• A ball rolling down a hill accelerates due to gravity.

• A book remains at rest on a table until a force is applied.

• A car speeds up as it moves down a slope.

• A rocket accelerates upwards due to the force of its engines.

A 10 kg object is accelerating at 3 m/s². What is the net force acting on the object?

• 10 N

• 30 N

• 3 N

• 13 N

A free body diagram shows a box on a flat surface with a force of 10 N applied to the right and a frictional force of 4 N to the left. What is the net force acting on the box?

• 6 N to the right

• 14 N to the right

• 6 N to the left

• 4 N to the left

A 15 kg object is at rest. A force of 45 N is applied. What will be the acceleration of the object?

• 1 m/s²

• 2 m/s²

• 3 m/s²

• 4 m/s²

If you were to run away from a moose using Newton's first law, what would be the best strategy?

• Stand still and hope the moose doesn't see you.

• Run in a straight line to maintain constant velocity.

• Change direction frequently to disrupt the moose's inertia.

• Jump up and down to confuse the moose.

A 20 kg object is moving with an acceleration of 2 m/s². If the frictional force is 10 N, what is the applied force?

• 30 N

• 40 N

• 50 N

• 60 N

A car of mass 1000 kg is accelerating at 5 m/s². What is the net force acting on the car?

• 5000 N

• 2000 N

• 1000 N

• 500 N

A 50 kg object is subjected to two forces: 100 N to the right and 30 N to the left. What is the acceleration of the object?

• 1.6 m/s²

• 2.0 m/s²

• 1.4 m/s²

• 4.0 m/s²