ADM Set 17 and 18 Summative- Solving Polynomials

$$x=-\frac{3}{2},\ 5$$

$$x=\frac{7\pm i\sqrt{71}}{4}$$

$$x=\frac{7\pm\sqrt{106}}{4}$$

$$x=3,\ -\frac{5}{2}$$

$$x=-5\pm i\sqrt{3}$$

$$x=\pm2i\sqrt{2}$$

$$x=-8\pm\sqrt{5}$$

$$x=5\pm3i$$

(0, 6)

(-1, 4)

(3, 6)

(-2, -4)

(-4, 10)

The student is right because it has exactly one solution.

The student is wrong because it has no real solutions.

The student is wrong because it has exactly two solutions.

$$\left(x^2+6\right)\left(x-5\right)$$

$$\left(x^2-5\right)\left(x+6\right)$$

$$\left(x+6\right)\left(x-5\right)$$

$$\left(x+3\right)\left(2x-6\right)$$

$$x\ =\ 2;\ x\ =\ \pm\sqrt[]{3}$$

$$x=3;\ x=\pm2$$

$$x=-3;\ x=\pm4$$

$$x=-3;\ x=\pm\sqrt[]{2}$$