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ҰБТ-мат 3 н 1-25

Authored by Пернебай Искахов

Mathematics

11th Grade

ҰБТ-мат 3 н 1-25
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25 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Есептеңіз: 3,6⋅810\sqrt[]{3,6\cdot810}

65

64

54

72

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

|−6+3∙|−4||+3∙|-15-4| өрнегінің мәнін табыңыз.

63

99

56

78

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Өрнектің мәнін табыңыз: ctg⁡(arccos⁡ 22+arcsin⁡ 22)\operatorname{ctg}\left(\arccos\ \frac{\sqrt[]{2}}{2}+\arcsin\ \frac{\sqrt[]{2}}{2}\right)

33\frac{\sqrt[]{3}}{3}

3\sqrt[]{3}

0

−1

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Өрнекті ықшамдаңыз: 116a8b4(−64a3b6)\frac{1}{16}a^8b^4\left(-64a^3b^6\right)

2a9b92a^9b^9

8a10b98a^{10}b^9

−4a11b10-4a^{11}b^{10}

−4a10b11-4a^{10}b^{11}

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

x2+2∣x∣+1=0x^2+2\left|x\right|+1=0 теңдеуін нақты сандар жиынында шешіңіз.

2

1

∅

−1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Теңдеулер жүйесін шешіңіз: { x2+xy+y2=13x^2+xy+y^2=13

x+y=4

(−4;8 ), (8;−4)

(0;4 ), (4;0)

(3;1 ), (1;3)

(5; −1),(−1;5)

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Функцияның туындысын табыңыз f(x)=2x2+42f\left(x\right)=\frac{\sqrt[]{2x^2+4}}{2}

x2x2+42x2+4\frac{x\sqrt[]{2x^2+4}}{2x^2+4}

2x2+42x\frac{\sqrt[]{2x^2+4}}{2x}

x2x2+42\frac{x\sqrt[]{2x^2+4}}{2}

x2x2+4\frac{x}{\sqrt[]{2x^2+4}}

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