Balancing Combustion Reactions of Sucrose

The video tutorial explains how to balance the chemical equation for the combustion of sucrose (C12H22O11) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). It highlights the importance of counting oxygen atoms correctly and suggests leaving O2 for last when balancing. The tutorial provides a step-by-step guide to balancing the equation, ensuring the correct number of carbon, hydrogen, and oxygen atoms. It also discusses the states of matter for the reactants and products, noting that the reaction is exothermic.

What type of reaction is the combustion of sucrose?

• Decomposition

• Single Replacement

• Combustion

• Synthesis

Why is it important to count oxygen atoms correctly in combustion reactions?

• Because they change the state of the reactants

• Because they are present in both reactants and products

• Because they affect the number of carbon atoms

• Because they determine the reaction speed

What is the recommended strategy for balancing combustion reactions?

• Leave O2 for last

• Start with oxygen

• Start with hydrogen

• Balance all elements simultaneously

When balancing the equation, what is the first element you should start with?

• Nitrogen

• Oxygen

• Carbon

• Hydrogen

How many oxygen atoms are there in the products after balancing the equation?

• 30

• 35

• 25

• 24

What is the total number of hydrogen atoms in the balanced equation?

• 22

• 24

• 11

• 12

What is the state of sucrose in the combustion reaction?

• Plasma

• Solid

• Liquid

• Gas

What is the state of water in the combustion reaction of sucrose?

• Gas

• Plasma

• Liquid

• Solid

What is the nature of the combustion reaction of sucrose?

• Exothermic

• Endothermic

• Neutral

• Catalytic

What is the final balanced equation for the combustion of sucrose?

• C12H22O11 + 12O2 → 12CO2 + 11H2O

• C12H22O11 + 11O2 → 12CO2 + 12H2O

• C12H22O11 + 12O2 → 11CO2 + 12H2O

• C12H22O11 + 13O2 → 12CO2 + 11H2O