Lewis Structures and Valence Electrons

Lewis Structures and Valence Electrons

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Mia Campbell

FREE Resource

The video tutorial explains how to write the Lewis structure for C2N2, also known as cyanogen. It begins by counting the valence electrons for carbon and nitrogen, totaling 18. The least electronegative elements, carbon, are placed in the center, with nitrogen on the ends. Initial bonds are formed, and adjustments are made to satisfy the octet rule by forming double and triple bonds. The final structure is reviewed, ensuring all atoms have complete octets.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons does a single carbon atom contribute in the Lewis structure of C2N2?

2

8

4

6

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of valence electrons used in the Lewis structure of C2N2?

18

16

20

22

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which element is placed at the center of the Lewis structure for C2N2?

Oxygen

Nitrogen

Hydrogen

Carbon

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in forming bonds in the Lewis structure of C2N2?

Completing octets for carbon

Placing a pair of electrons between atoms

Forming a triple bond

Placing lone pairs on nitrogen

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why do we need to form double bonds in the Lewis structure of C2N2?

To achieve octets for nitrogen

To achieve octets for carbon

To increase the number of atoms

To reduce the number of valence electrons

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the carbon atoms when a double bond is formed in the Lewis structure?

They lose electrons

They become more electronegative

They form a new molecule

They gain a complete octet

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of forming a triple bond in the Lewis structure of C2N2?

To make the structure more stable

To decrease the number of bonds

To achieve octets for all atoms

To increase the number of valence electrons

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