Valence Electrons in NBr3

The video tutorial explains how to write the Lewis structure for nitrogen tribromide (NBr3). It begins by counting the valence electrons for nitrogen and bromine, totaling 26 electrons. The least electronegative element, nitrogen, is placed at the center with bromine atoms around it. Initial bonds are formed using six electrons, and the octets for bromine are completed using 24 electrons. The remaining two electrons form a lone pair on nitrogen, finalizing the Lewis structure.

What is the total number of valence electrons in NBr3?

• 30

• 26

• 24

• 28

Which element is placed at the center of the NBr3 Lewis structure?

• Bromine

• Nitrogen

• Oxygen

• Hydrogen

How many valence electrons are used to form bonds between nitrogen and bromine atoms in NBr3?

• 10

• 4

• 6

• 8

How many valence electrons does each bromine atom have around it after completing the octet?

• 9

• 7

• 6

• 8

What is the total number of valence electrons used after completing the octets for bromine atoms?

• 20

• 22

• 24

• 26

Where are the last two valence electrons placed in the NBr3 Lewis structure?

• On the nitrogen atom as a lone pair

• Between two bromine atoms

• On a bromine atom

• In the center of the structure

What is the significance of the lone pair on the nitrogen atom in NBr3?

• It is shared with bromine atoms

• It completes the nitrogen's octet

• It is not significant

• It forms a bond with another molecule