B(OH)3 Lewis Structure Concepts

B(OH)3 Lewis Structure Concepts

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Emma Peterson

FREE Resource

The video tutorial explains how to draw the Lewis structure for B(OH)3. It starts by calculating the total valence electrons, considering Boron, Oxygen, and Hydrogen. The structure is built by placing Boron at the center and arranging OH groups around it. The video details the use of valence electrons to form bonds and fill octets, noting that Boron is an exception to the octet rule. The tutorial concludes with a completed Lewis structure for B(OH)3.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons are there in total for the B(OH)3 Lewis structure?

18

21

24

27

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the B(OH)3 Lewis structure, which atom is placed at the center?

Boron

Oxygen

Hydrogen

Carbon

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons are used to form chemical bonds in the B(OH)3 structure?

12

24

6

18

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of valence electrons used to fill the octets for the Oxygens in B(OH)3?

6

12

24

18

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is Boron an exception in the B(OH)3 Lewis structure?

It does not form any bonds.

It forms double bonds with Oxygen.

It is stable with only six valence electrons.

It has more than eight valence electrons.