Semi-Circles in the Complex Plane

Semi-Circles in the Complex Plane

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial guides viewers through a complex algebraic problem involving the breakdown of arguments into separate components, plotting diagrams, and deriving Cartesian equations. The instructor emphasizes the importance of understanding reference points and provides step-by-step instructions for finding intercepts and solving equations. The tutorial concludes with a focus on ensuring accuracy in diagramming and calculations.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of breaking apart a single argument into two separate arguments in complex numbers?

To simplify the calculation of real numbers

To identify the reference points for plotting

To eliminate imaginary components

To convert them into polar coordinates

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When plotting reference points for complex numbers, why are they represented as hollow circles?

To show they are fixed points

To indicate they are not part of the solution

To differentiate them from filled circles

To highlight their importance

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What two pieces of information are needed to define a semi-circle in the complex plane?

Length and width

Area and perimeter

Center and radius

Diameter and circumference

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which formula is used to calculate the radius of a semi-circle in the complex plane?

Area formula

Circumference formula

Distance formula

Volume formula

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can't a domain restriction be applied to the Cartesian equation of a semi-circle?

It would create multiple solutions

It would result in a full circle

It would exclude the imaginary axis

It would only apply to the real axis

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the Cartesian equation of a semi-circle with a center at (0, 2) and a radius of √5?

(x - 2)^2 + y^2 = 5

x^2 + y^2 = 5

x^2 + (y - 2)^2 = 5

x^2 + (y + 2)^2 = 5

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can you find the y-intercept of a semi-circle in the complex plane?

By setting y to zero

By setting x to zero

By using the distance formula

By calculating the midpoint

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