Calculus Concepts and Trigonometric Functions

Calculus Concepts and Trigonometric Functions

Assessment

Interactive Video

Mathematics

11th - 12th Grade

Practice Problem

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial introduces trigonometric expansions, emphasizing their importance in calculus. It reviews calculus concepts like differentiation and integration, and explores function families such as polynomials, logs, and exponentials. The tutorial applies first principles to trigonometric functions, highlighting common errors in expansions. The goal is to equip students with the skills to handle trigonometric functions in calculus.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to have a purpose when learning trigonometric expansions?

To impress your teacher

To skip learning calculus

To avoid shuffling symbols without understanding

To memorize formulas easily

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What was the first concept learned in calculus?

Integration

Algebra

Differentiation

Trigonometry

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which type of functions were initially focused on in differentiation?

Trigonometric functions

Polynomial functions

Exponential functions

Logarithmic functions

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the process of undoing differentiation called?

Multiplication

Integration

Exponentiation

Logarithm

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which new family of functions was introduced after polynomial functions?

Complex functions

Trigonometric functions

Logarithmic and Exponential functions

Rational functions

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the missing link in calculus that has not been explored yet?

Polynomial functions

Trigonometric functions

Logarithmic functions

Exponential functions

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for the derivative of a function using first principles?

f'(x) = x + h

f'(x) = limit as h approaches 0 of [f(x+h) - f(x)]/h

f(x) = sin(x)

f(x) = x^2

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